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maxonik [38]
3 years ago
7

What does every chemical reaction involve?

Chemistry
2 answers:
IgorC [24]3 years ago
7 0

breaking bonds in reactants and forming new bonds in products. Breaking bonds requires energy, and forming bonds releases energy.

sergey [27]3 years ago
6 0

breaking bonds involve in every chemical reaction

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Alborosie

Answer:

When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” Mono-” indicates one, “Di-” indicates two, “Tri-” is three, “Tetra-” is four, “Penta-” is five, and “Hexa-” is six, “Hepta-” is seven, “Octo-” is eight, “Nona-” is nine, and “Deca-” is ten.

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2 years ago
What will most likely happen when stress is applied to an equilibrium reaction? The system will not respond to the stress. The s
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The system will change its concentration to shift to a new equilibrium position.

Explanation:

For example  in the Haber Process

N2  +  3H2  ⇄  2NH3

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What causes red blood cells to become sickle-shaped in a person with sickle
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2 years ago
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Which of the following is not a form of radiation? Radio waves or sound waves or microwaves or gamma waves
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3 0
2 years ago
A compound containing chromium, Cr; chlorine, Cl; and oxygen, O, is analyzed and found to be 33.6% chromium, 45.8% chlorine, and
Assoli18 [71]

Answer

The empirical formula is CrO₂Cl₂

Explanation:

Empirical formula is the simplest whole number ratio of an atom present in a compound.

The compound contain, Chromium=33.6%

                                         Chlorine=45.8%

                                          Oxygen=20.6%

And the molar mass of Chromium(Cr)=51.996 g mol.

                 Chlorine containing molar mass (Cl)= 35.45    g mol.

                 Oxygen containing molar mass (O)=15.999  g mol.

Step-1

 Then,we will get,

Cr=\frac{1}{51.996} \times33.6=0.64 mol

Cl= \frac{1}{35.45} \times45.8=1.29 mol.

O=\frac{1}{15.99} \times=1.28 mol.

Step-2

Divide the mole value with the smallest number of mole, we will get,

Cr= \frac{0.64}{0.64} =1

Cl= \frac{1.29}{0.64} =2

O= \frac{1.28}{0.64} =2

Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)

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3 years ago
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