Question

A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm.

Answer 1

Complete question:

A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm. Find the number of moles of the gas.

Answer:

The number of mole of the gas is 0.164 mol.

Explanation:

Given;

volume of the ideal gas, V = 2.48 L

temperature of the gas, T = 0.964 °C = 273K + 0.964 = 273.964 K

pressure of the gas, P = 1.49 atm

The number of moles of the gas is calculated by using ideal gas equation;

PV = nRT

where;

n is the number of moles of the gas

R is ideal gas constant = 0.082057 L.atm/mol.K

$n = \frac{PV}{RT} \\\\n = \frac{1.49 \ atm \ \times \ 2.48 \ L}{0.082057 \ L.atm/mol.K \ \ \times \ 273.964 \ K} \\\\n = 0.164 \ mol$

Therefore, the number of mole of the gas is 0.164 mol.