A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm.
1 answer:
Complete question:
A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm. Find the number of moles of the gas.
Answer:
The number of mole of the gas is 0.164 mol.
Explanation:
Given;
volume of the ideal gas, V = 2.48 L
temperature of the gas, T = 0.964 °C = 273K + 0.964 = 273.964 K
pressure of the gas, P = 1.49 atm
The number of moles of the gas is calculated by using ideal gas equation;
PV = nRT
where;
n is the number of moles of the gas
R is ideal gas constant = 0.082057 L.atm/mol.K
Therefore, the number of mole of the gas is 0.164 mol.
You might be interested in
Answer : The mass of a sample of water is, 888.89 grams
Explanation :
Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.
Formula used :
where,
q = heat = 2000 kJ = (1 kJ = 1000 J)
L = latent heat of vaporization of water =
m = mass of sample of water = ?
Now put all the given values in the above formula, we get:
(1 kg = 1000 g)
Therefore, the mass of a sample of water is, 888.89 grams
Answer:
s = 0.337 m
Explanation:
First, we will find the angular displacement of the reel:
where,
θ = angular displacement = ?
ω = angular speed = 1.9 rad/s
t = time taken = 7.1 s
Therefore,
θ = (1.9\ rad/s)(7.1 s)
θ = 13.5 rad
Now, we will find out the length of tape:
s = rθ
where,
s = length of tape = ?
r = radius of reel = 2.5 cm = 0.025 m
Therefore,
s = (0.025 m)(13.5 rad)
<u>s = 0.337 m</u>