Answer:
Explanation:
1) Force Friction = Normal Force * Coefficient of Friction
Force Friction = Mass * Gravity * Coefficient of Friction
2) F = ma
Force = mass * acceleration
Force Friction (from #1) = mass * acceleration
acceleration = Force Friction / Mass
Answer:
is a sign of a chemical change
Explanation:
The tablet reacts with the water to form carbon dioxide
After impact velocity = 14.968 ft/s
Weight and mass of Bullet and wooden block:
Bullet: w = 1oz = 1/16 lb m = 0.001941 lb
wooden block : W = 5lb M = 0.15528 lb
velocity of block and bullet immediately after impact:
Σmv1 + ΣImp = mv2
Resolving vertical component
( m× v₀cos30⁰) + 0 = ( m+M) v'
v' = ( m× v₀cos30⁰)/ (m+M)
v' = 14.968 ft/s
Horizontal and vertical component of the impulse exerted by block on the bullet:
Here we will apply the principle of impulse and momentum.
Horizontal component:
-mv₀ cos30⁰ + RxΔt =0
RxΔt = mv₀sin30⁰
= 0.001941 × 1400sin30⁰
RxΔt = 1.3587 lb.s
Vertical component:
-mv₀cos30⁰ + RyΔt = -mv'
RyΔt = m( v₀cos30⁰-v')
RyΔt = 0.001941(1400cos30⁰ - 14.968)
= 2.32 lb.s
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Every organism may classified into seven level of classifications, such that each level contains organisms with similar characteristics. Kingdom is the largest and the broadest level of classification while species is the smallest and most specific level of classification. Therefore from the largest to the smallest the order is as follows:
Kingdom
Phylum
Class
Order
Family
Genus
Species
The time taken before the two soccer players are 24.7 m apart is 3 seconds.
Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.
The distance between Jane and Mary after 4.08 seconds is 33.58 m.
<h3>
Resultant velocity of Mary and Jane</h3>
Vertical component of the velocity;
Jane: Vy1 = V sinθ
Vy1 = 5.07 m/s x sin(60.2)
Vy1 = 4.4 m/s
Horizontal components of the velocity;
Jane: Vx1 = V cos θ
Vx1 = 5.07 m/s x cos60.2
Vx1 = 2.52 m/s
mary: Vx2 = 4.43 m/s
total horizontal components of the velocity = 4.43 m/s + 2.52 m/s = 6.95 m/s
<h3>Resultant velocity</h3>
V = √Vy² + Vx²
V = √(4.4² + 6.95²)
V = 8.23 m/s
<h3>Time taken before they are 24.7 m apart</h3>
t = 24.7 m / 8.23 m/s
t = 3 seconds
Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.
<h3>Distance between Jane and Mary after 4.08 seconds</h3>
d = vt
d = 8.23 m/s x 4.08 s
d = 33.58 m
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