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3 years ago

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Differences between selenium tellurium and polonium

1 answer:

dsp733 years ago

5 0

Explanation:

Selenium and tellurium are rare elements, respectively, in order of crustal abundance. However, polonium, on account of its radioactive decay, is less abundant. The main source of selenium and tellurium is the anode slime deposited during the electrolytic refining of copper.

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BF3 is the Lewis____in the

kakasveta [241]

Answer:

A

Explanation:

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For each of the following, indicate if the number of half-lives elapsed is:

Hunter-Best [27]

Answer:

<u>a. one half-life</u>

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Explanation:

The number of half-lives elapsed, n, is calculated dividing the time by the half-life time:

n = time / half-life time

<u>a. A sample of Ce-141 with a half-life of 32.5 days after 32.5 days</u>

n = 32.5 days / 32.5 days = 1 half-life

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<u>b. A sample of F-18 with a half-life of 110 min after 330 min</u>

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<u>c. A sample of Au-198 with a half-life of 2.7 days after 5.4 days</u>

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alexira [117]

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The distance between two points on a map is 0.704 kilometers. What is the distance in meters?

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Calculate the molarity of 198 g of barium iodide (Bal2) in 2.0 l of solution

nikitadnepr [17]

Answer: The molarity of 198 g of barium iodide $(BaI_{2})$ in 2.0 L of solution is 0.253 M.

Explanation:

Given: Mass = 198 g

Volume = 2.0 L

Molarity is the number of moles of solute present in liter of a solution.

Moles is the mass of a substance divided by its molar mass. So, moles of barium iodide (molar mass = 391.136 g/mol) is calculated as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{198 g}{391.136 g/mol}\\= 0.506 mol$

Now, molarity is calculated as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.506 mol}{2.0 L}\\= 0.253 M$

Thus, we can conclude that the molarity of 198 g of barium iodide $(BaI_{2})$ in 2.0 L of solution is 0.253 M.

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3 years ago