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Stolb23 [73]
3 years ago
8

2. Kevin is a member of the school's track and field team. His favorite event is throwing the shot

Physics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

F=ma

165/28.5=57.89kg

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The length of a rectangle is four times its width. The perimeter of the rectangle is at most 130 cm. Which inequality models the
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The answer would be the one where the left side is less than or equal to 130 because 130 has to be the greatest value and the value of the w's cannot exceed 130, but they can equal it
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A 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.8 m/s left. Afterwards, the 282 kg car m
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Answer: momentum afterwards = 1040.4kgm/s

Explanation:

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You are presented with several wires made of the same conducting material. The radius and drift speed are given for each wire in
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\begin{array}{ccc}&\text{Radius} & \text{Drift Speed}\\d) & 2 \; r &2.5 \; v\\a) & 3 \; r &1 \; v\\b) & 4 \; r &0.5 \; v\\c) & 1 \; r &5 \; v\\\end{array}

<h3>Explanation</h3>

I = v \cdot A \cdot n \cdot q,

where

  • I is the current;
  • v is the drift speed;
  • A is the cross-section area of the wire,
  • n is the number of charge carrier per unit volume, and
  • q is the charge on each charge carrier.

Area of a circular cross-section:

A = \pi \cdot r^{2},

where

  • r is the radius of the wire.

n and q are the same for all four samples, for they are made out of the same material.

As a result, I of each wire is directly proportional to v \cdot r^{2} where the value of \pi \cdot n \cdot q is constant.

For each of the four wires:

\begin{array}{ccc|c}\\& r & v &I \propto v\cdot r^{2}\\a) & 3 & 1 & 9\\b) & 4 & 0.5 & 8\\c) & 1 & 5 & 5\\d) & 2 & 2.5 & 10\\\end{array}.

How do the four wires rank by their current?

d > a > b > c.

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A ball whirls around in a vertical circle at the end of a string. The other end of the string is fixed at the center of the circ
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Answer:

T_b=m(g+\frac{v_b^2}{R})

Explanation:

At the bottom the tension would be upwards and the weight downwards, their difference being the centripetal force. Taking the upwards direction as positive we then have:

T_b-mg=F_{cp}=ma_{cp}=m\frac{v_b^2}{R}

where we have used the equation for centripetal acceleration. Thus we have:

T_b=m(g+\frac{v_b^2}{R})

4 0
3 years ago
A + B + C → D + E
MAVERICK [17]
B) the mass of the reactant equals the mass of the product.
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