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3 years ago

The typical unit for a period used with Kepler's third law is

1 answer:

6 0

Well, if you're using the law to work with periods of Earth satellites,
then the most convenient unit is going to be 'hours' for the largest
orbits, or 'minutes' for the LEOs.

But if you're using it to work with periods of planets, asteroids, or
comets, then you'd be working in days or years.

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What is the energy of a 4kg apple that is sitting on a 2 m high tree branch?

miv72 [106K]

78.4 joules is the energy of a 4 kg apple that is sitting on a 2 m high tree branch.

<u>Explanation: </u>

When an apple falls to the ground from a tree, its positional energy (stored as potential gravitational energy) turns into kinetic energy, during a fall. Chemical potential energy is chemical energy because it is food and potential energy as it can still have ability to move. So, in the given case, kinetic energy is zero.

To find potential energy, the formula would be

$\text { potential energy }(P . E)=m \times g \times h$

Where, given

m – Mass – 4 kg

$g-\text { Earth'sgravity }-9.8 \mathrm{m} / \mathrm{s}^{2}$ (Known value)

h – Height - 2 m

Substitute these values, we get

$P . E=4 \times 9.8 \times 2=78.4 \text { joules }$

8 0

3 years ago

Rank in order, from largest to smallest, the values of the resistances r1 tor3.

Greeley [361]

Resistor 1 and three are in series so the total resistance is 1.

8 0

3 years ago

The rating of a light bulb at 100 watts indicates

Slav-nsk [51]

That marking means that when the expected voltage is connected
between the two contacts of the bulb, it will dissipate 100 joules of
energy every second, in the form of heat and light.

8 0

4 years ago

A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for

nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ( $W$ ), measured in newtons, is:

$W = m\cdot g$ (1)

Where:

$m$ - Mass of the block of ice, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 14\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the magnitudes of the weight and normal force of the block of ice are, respectively:

$N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$N = W = 137.298\,N$

And the pull force is:

$F_{pull} = 98\,N$

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

$m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}$ (2)