Answer:
The answer is 0.370moles (3 s.f)
Explanation:
Step 1: write the balanced equation for the reaction
Equation for the reaction:
2Al(s) + 6HCl(g) ---------> 2AlCl3(g) + 3H2(g)
Step 2: Equate the mole of the needed substances
So therefore,
2moles of aluminum will produce 2 moles of aluminum chloride
Note that:
Relative atomic mass of Al = 27 g/mole
And, 27g of Al = 1 mole of Al.
Step 3: Solve for the required number of mole.
2moles of Al = 2moles of AlCl3
Same as
1 mole of Al = 1 mole of AlCl3
27g of Al = 1 mole of AlCl3
10g of Al = (1/27 * 10g) of AlCl3
10g of Al = 0.370moles of AlCl3
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