Answer:
V1= 0.305L
Explanation:
To find the initial volume of 1.25M potassium fluoride needed to make tge dilution specified in the question, we can use: C1 × V1 = C2 × V2
Since the question wants the volume in litres, convert 455 mL to L
455/ 1000
= 0.455 L
Now make the substitution
1.25 × V1 = 0.838 × 0.455
Rearrange to make V1 the subject
V1=

Answer:
The mass of water is 36 g.
Explanation:
Mass of hydrogen = 4 g
Mass of water = ?
Solution:
First of all we will write the balance chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen = mass / molar mass
Number of moles of hydrogen = 4 g/ 2 g/mol
Number of moles of hydrogen = 2 mol
Now we compare the moles of water with hydrogen from balance chemical equation.
H₂ : H₂O
2 : 2
Mass of water = moles × molar mass
Mass of water = 2 mol × 18 g/mol
Mass of water = 36 g
If the water oxygen is in excess than mass of water would be 36 g.
Usually in this context you would be referring to the boiling and freezing point of a NaCl <em>solution</em> (saltwater) compared to pure H_{2}O. Sematics would be different for NaCl compound itself, you would say melting and boiling point for a solid substance- and the temperatures would be very, very radical (high).
The boiling point of pure water is 100 degrees C (212 F), and the freezing/melting point is below 0 degrees C (32 F). For a salt water solution, the boiling point is raised and the melting point is lowered. This means that water will stay liquid for an increased range of temperature. Depending on the amount of NaCl solute in the water, the boiling and melting points may change a few degrees.
Answer:
<h2><em><u>A</u></em><em><u>.</u></em><em><u> </u></em><em><u>Cl2</u></em><em><u>(</u></em><em><u>g</u></em><em><u>)</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>2NaBr</u></em><em><u>(</u></em><em><u>aq</u></em><em><u>)</u></em><em><u> </u></em><em><u>--</u></em><em><u>></u></em><em><u> </u></em><em><u>2NaCl</u></em><em><u>(</u></em><em><u>aq</u></em><em><u>)</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>Br2</u></em><em><u>(</u></em><em><u>g</u></em><em><u>)</u></em></h2>
Explanation:
This is because,
Chlorine atoms (Cl2) displaces with Bromine atoms (Br) in Sodium bromide (2NaBr) solution to give a result as, Sodium Chloride (2NaCl) and left out atom Bromine (Br)
Br2
I looked it up and it said that Bromine's formula is Br2