1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksivusya [100]
2 years ago
12

10-kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the con

tainer. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.
Chemistry
1 answer:
Mariulka [41]2 years ago
3 0

Answer:

Temperature = 0.605°C

Total enthalpy at 300kpa = 545.2 kJ

Total enthalpy at 600kpa = 846.45 kJ.

Explanation:

Checking the table for 134a pressure table. It is given that the specific volume of saturated liquid and the specific volume of the saturated vapor of 280kpa is 0.0007699 m^3/kg and 0.072352 m^3/kg respectively.

Also, the specific volume of saturated liquid and the specific volume of the saturated vapor of 320kpa is 0.0007772 m^3/kg and 0.063604 m^3/kg respectively.

The first thing to do is to determine the value for the specific volume of saturated liquid.

At 300 kpa, the specific volume of saturated liquid,n is given below as;

300 - 280/ 320 - 280 = (n - 0.0007699)/ 0.0007772 - 0.0007699.

Therefore, n = specific volume of saturated liquid = 0.0007735 m^3/kg.

300 - 280/ 320 - 280 = n - 0.072352/ (0.063604 - 0.072352).

n = 0.0679 m^3/kg.

The second thing to do is to determine the value of the specific volume.

Specific volume = 14 × 10^-3/ 10 = 0.0014 m^3/kg.

Determine the enthalpy of the mixture,b(I). This is given below as;

300 - 280/ 320 - 280 = b(I) - 199.54/ (196.7 - 199.54).

b(I) = 198.125 kJ/Kg.

Hence, b = [ 300 - 280/ 320 - 280 = j - 50.18 / 55.16 - 50.18] + [ ( 0.0014 - 0.00077735) / 0.067978 - 0.00077735] × 198.125.

b = 54.517 KJ/Kg.

Total enthalpy = 10 × 54.517 = 545.17 kJ.

Temperature can be Determine as below;

300 - 280/ 320 - 280 = T + 1.25 / 2.46 - 1.25.

Temperature = 0.605°C.

Hence, at 600kpa, the total enthalpy = [81.51 + ( 0.0014 - 0.0008199/ 0.034295 - 0.0008199) × 180.90] × 10

Total enthalpy at 600kpa = 846.45 kJ.

You might be interested in
In the molecular orbital model of cyclobutadiene, how many -antibonding molecular orbitals are there?
Citrus2011 [14]

There are one antibonding molecular orbitals present in molecular orbital model of c.

The cyclobutadiene has a pi system comprised of four  individual atomic p - orbital and thus should have a four pi   molecular orbitals. The compound is the prototypical antiaromatic hydrocarbon with 4 \pi - electrons .  Its rectangular structure is the result of jahn teller reaction which disorder the molecule and lowers its symmetry , converting the triplet to a singlet ground state. It is a small annulene . The  delocalisation energy of the  \pi   electrons of the cyclobutene is predicted to be zero .

To learn more about antibonding molecular orbitals click here

brainly.com/question/14970060

#SPJ4

4 0
2 years ago
In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and
Brums [2.3K]
14.5 % carb
5.7% sugar
5.1% fiber
5.4% protein
0.4% fat
7 0
2 years ago
What is the name of the following compound? A line-angle formula shows a ring with six vertices and a circle inscribed. A Cl ato
ozzi

Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.

Explanation:

A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.

Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as <em>para </em>or <em>p </em>configuration.

Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).

Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.

4 0
3 years ago
In order to reduce the exposure to organic solvents like turpentine, some art instructors recommend the students clean brushes a
kykrilka [37]
Generally speaking, organic molecules tend to dissolve in solvents that have similar physical properties. A good rule of thumb is that "like dissolves like". Meaning, polar compounds can dissolve polar compounds and nonpolar compounds can dissolve nonpolar compounds.

To apply this to the current problem, we are told that the brushes are being cleaned with vegetable oil or mineral oil. In this case, the oils are used as solvents. In order for these solvents to be effective, the compounds they are trying to dissolve must be similar in structure and properties to other oils. Therefore, vegetable oil or mineral oil will be most effective in removing oil-based paints, as these will have the similar properties needed to dissolve in the oil solvents.
6 0
3 years ago
How would a collapsing universe affect light emitted from clusters and superclusters? A. Light would acquire a blueshift. B. Lig
Lady_Fox [76]

Answer:

Choice A: Light would acquire a blueshift.

Explanation:

When a universe collapses, clusters of stars start to move towards each other. There are two ways to explain why light from these stars will acquire a blueshift.

Stars move toward each other; Frequency increases due to Doppler's Effect.

The time period t of a beam of light is the same as the time between two consecutive peaks. If \lambda is the wavelength of the beam, and both the source and observer are static, the time period T will be the same as the time it takes for light travel the distance of one \lambda (at the speed of light in vacuum, c).

\displaystyle t = \frac{\lambda}{c}.

Frequency f is the reciprocal of time period. Therefore

\displaystyle f = \frac{1}{t} = \frac{c}{\lambda}.

Light travels in vacuum at a constant speed. However, in a collapsing universe, the star that emit the light keeps moving towards the observer. Let the distance between the star and the observer be d when the star sent the first peak.

  • Distance from the star when the first peak is sent: d.
  • Time taken for the first peak to arrive: \displaystyle t_1 =\frac{d}{c}.

The star will emit its second peak after a time of. Meanwhile, the distance between the star and the observer keeps decreasing. Let v be the speed at which the star approaches the observer. The star will travel a distance of v\cdot t before sending the second peak.

  • Distance from the star when the second peak is sent: d - v\cdot t.
  • Time taken for the second peak to arrive: \displaystyle t_2 =t + \frac{d - v\cdot t}{c}.

The period of the light is t when emitted from the star. However, the period will appear to be shorter than t for the observer. The time period will appear to be:

\begin{aligned}\displaystyle t' &= t_2 - t_1\\ &= t + \frac{d - v\cdot t}{c} - \frac{d}{c}\\&= t + (\frac{d}{c} - \frac{v\cdot t}{c}) -\frac{d}{c}\\&= t - \frac{v\cdot t}{c} \end{aligned}.

The apparent time period t' is smaller than the initial time period, t. Again, the frequency of a beam of light is inversely proportional to its period. A smaller time period means a higher frequency. Colors at the high-frequency end of the visible spectrum are blue and violet. The color of the beam of light will shift towards the blue end of the spectrum when observed than when emitted. In other words, a collapsing universe will cause a blueshift on light from distant stars.

The Space Fabric Shrinks; Wavelength decreases as the space is compressed.

When the universe collapses, one possibility is that clusters of stars move towards each other. Alternatively, the space fabric might shrink, which will also bring the clusters toward each other.

It takes time for light from a distant cluster to reach an observer on the ground. The space fabric keeps shrinking while the beam of light makes its way through the space. The wavelength of the beam will shrink at the same rate. The wavelength of the beam of light will be shorter by the time the beam arrives at its destination.

Colors at the short-wavelength end of the visible spectrum are blue and violet. Again, the color of the light will shift towards the blue end of the spectrum. The conclusion will be the same: a collapsing universe will cause a blueshift on light from distant stars.

8 0
3 years ago
Other questions:
  • What occurs only on the surface of the substance
    11·1 answer
  • Water vapor particles are most likely to phase change into liquid particles if the vapor particles come into contact with
    7·1 answer
  • Why do pumps require energy?
    13·2 answers
  • Calculate the solubility of CuX (Ksp=[Cu2+][X2−]=1.27×10−36) in a solution that is 0.200 M in NaCN.
    11·2 answers
  • Part C<br> What is a useful application for this new material?
    11·2 answers
  • Which organisms break down dead matter and waste into nonliving elements?
    14·2 answers
  • If I have one mole of cupcakes, how many cupcakes do I have?
    14·1 answer
  • This element has 80 electrons and is considered a transitional element. What am I?
    13·1 answer
  • Which of these is a behavioral adaptation?
    9·2 answers
  • Please help asap chemistry homework
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!