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Mariulka [41]
3 years ago
15

The magnitude of vector vector A is 84.9 m and it points in the +y axis direction. The magnitude of vector vector B is 195.0 m a

nd it points at an angle of 41.0° counterclockwise from +x axis. The magnitude of vector vector C is 126.2 m and it points in the +x axis direction.
Physics
1 answer:
Luda [366]3 years ago
6 0

Solution:

The magnitude of A vector is 84.9 m in the positive y-axis direction.

So the X component of A =0

     the Y component of A = 84.9 m

Now the magnitude of B vector is 195 m and it makes an angle of 41° in the direction from the positive x-axis direction.

So  the X component of B = B cos 41°

                                           = 195 x cos 41°

                                           = 195 x 0.75   = 146.25 m

   the Y component of B = B sin 41°

                                           = 195 x sin 41°

                                           = 195 x 0.65   = 126.75 m

Now it is given that vector C has a magnitude of 126.2 m and it makes a direction towards the positive x-axis.

So the X component of C =126.2 m

     the Y component of C = 0

Comparing all these, we get

1. B vector has the largest X component

2. B vector has the largest Y component

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d. Boyle's

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Stating this mathematically. this implies that:

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Which term describes an educated guess about the outcome of an
bezimeni [28]

Answer:

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Refer to a trial solution to a problem as a hypothesis, often called an "educated guess" because it provides a suggested outcome based on the evidence.

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Answer:

The appropriate solution is "61.37 s".

Explanation:

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Now,

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Travelling such distance for 300 m will be:

⇒ v = \frac{d}{t} \ sot \ t

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On putting the values, we get

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Throughout the opposite direction, when the boat seems to be travelling then,

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⇒ v=\frac{v}{t} \ sot \ t

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Q = C.v
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Answer:

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