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gtnhenbr [62]
3 years ago
9

What properties of the elements did Mendeleev study?

Chemistry
1 answer:
masha68 [24]3 years ago
3 0

Answer:

Petersburg, Russia), Russian chemist who developed the periodic classification of the elements. Mendeleev found that, when all the known chemical elements were arranged in order of increasing atomic weight, the resulting table displayed a recurring pattern, or periodicity, of properties within groups of elements.

Explanation:

Hope this helps!!!

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Which geological feature is caused mainly by glacial erosion? O A. geyser O B. fault line O c. lava flow O D. U-shaped valley​
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Answer:

i think it is C

Explanation: hope this helps :)

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Which one of the following pairs of separation techniques will BOTH separate salt from a mixture of salt and water?
Natali5045456 [20]

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What are the options and i dont know what the options are but if one of them is distilation im 99.9% sure that is the answer.

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One of the products of photosynthesis is<br> carbon dioxide.<br> fire.<br> oxygen gas.<br> mass.
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3 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
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If you had excess aluminum, how many moles of aluminum chloride could be produced from 28.0 g of chlorine gas, Cl2?
Mice21 [21]

Answer:

Yes chemistry. Try to add then multiply the top. Get the moles and you will find it.

Explanation:

Try to add then multiply the moles in the equation

6 0
3 years ago
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