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3 years ago

I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!

Physics

2 answers:

Charra [1.4K]3 years ago

4 0

I'm not sure what your asking, exsplain please?

( I'll edit this when I get details <3 )

Makovka662 [10]3 years ago

3 0

What do you mean by that

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A pool ball moving 1.83 m/s strikes an identical ball at rest. Afterward, the first ball moves 1.15 m/s at a 23.3° angle. What i

Oksi-84 [34.3K]

Answer:

v_{1fy} = - 0.4549 m / s

Explanation:

6 0

3 years ago

A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit

likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density $\mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m$

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 120=753.6rad/sec$

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by $P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt$

From the relation we can see that power $P\ \propto\ A^2$

So if amplitude is halved then power will be $\frac{1}{4}$ times

So power will be equal to $\frac{0.2023}{2}=0.0505watt$

4 0

3 years ago

Bats have poor vision and use echo-location to find their way.The frequency produced by bats is 100kHz. If the speed of the soun

irga5000 [103]

The distance covered is 25.9 m.

We know that the speed of sound refers to the speed with which an sound moves in an object.

Given that;

speed of sound = 345m/s

Time taken = 0.15s

We know that;

v = 2d/t

v = speed of sound

d = distance

t = time taken

vt = 2d

d = vt/2

d = 345m/s * 0.15s/2

d = 25.9 m

Learn more about speed of sound:brainly.com/question/15137350

#SPJ1

5 0

2 years ago

When two plates of differing densities collide, how might the density of each plate affect which plate is pulled beneath the oth

OlgaM077 [116]

Pull the plates apart and you will knwo what it is lmaoo

5 0

3 years ago

Considerando que los coeficientes de dilatación de los siguientes metales son: hierro 11.7 x 10-6; plomo 27.3 x 10-6; cobre 16.7

Rasek [7]

Answer:

el plomo será el más largo

Explanation:

Dado que;

longitud inicial (l1) = 4m

Longitud final l2

aumento de temperatura (θ) = 10 ° C

Coeficiente de expansión lineal α

Ahora para el hierro;

α = 11,7 x 10-6

Desde;

l2-l / l1θ = α

l2 = α l1θ + l1

l2 = l1 (αθ + 1)

l2 = 4 ((11,7 x 10-6 * 10) + 1)

l2 = 4.00044 m

Para el plomo

l2 = 4 ((27,3 x 10-6 * 10) + 1)

l2 = 4,00109 m

Para cobre

l2 = 4 ((16,7 x 10-6 * 10) + 1)

l2 = 4.000668 m

Por lo tanto, el plomo será el más largo

7 0

3 years ago