Using the formula 2n² put in the value of n which is 4
the answer is 2×4² which is 2×16
The answer is 32.
this is the maximum no of electron acceptable into the electron shell.
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Answer:
b) [bicarbonate]/[carbonic acid] = 9.4
Explanation:
The pH of a buffer system is given by the Henderson-Hasselbach equation:
- pH = pKa + log ([bicarbonate] / [carbonic acid])
Where pka = -log (Ka) = -log(4.2x10⁻⁷) = 6.38
Now we <u>solve for [bicarbonate] / [carbonic acid]</u>:
- 7.35 = 6.38 + log ([bicarbonate] / [carbonic acid])
- 0.97 = log ([bicarbonate] / [carbonic acid])
= [bicarbonate] / [carbonic acid]
- [bicarbonate] / [carbonic acid] = 9.33 ≈ 9.4
So the answer is b).
Answer:
D:PS
Explanation:
Looking at the table we can see that PS floats on dish soap and sinks in water.
Answer:
they will have 100% kinetic energy
Explanation:
all the potential energy has been used when it is at the bottom of the ramp
<u>Given:</u>
E⁰cathode = -0.76 V
E⁰anode = -0.91 V
<u>To determine:</u>
The equilibrium constant K for the reaction-
Cr(s) + Zn2+ (aq) ↔ Cr2+(aq) + Zn(s)
<u>Explanation:</u>
The relation between, E⁰cell and Keq is-
E⁰cell = (0.0592/n) log(Keq)
E⁰cell = E⁰cathode-E⁰anode = -0.76-(-0.91) = 0.15 V
n = # electrons in the reaction = 2
0.15 = (0.0592/2) * logKeq
logKeq = 5.07
Keq = 10⁵.⁰⁷ = 1.17*10⁵
Ans: the equilibrium constant is 1.17*10⁵
