3 years ago

7 points

Physics

1 answer:

zlopas [31]3 years ago

5 0

Answer:

<h2>displacement = 23.32m</h2><h2>___________________</h2><h2>FOLLOW ME</h2>

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A rectangular gasoline tank can hold 50.0 kg of gasoline when full. What is the depth of the tank if it is 0.500-m wide by 0.900

sweet-ann [11.9K]

Answer:

0.16 m

Explanation:

A rectangular gasoline tank can hold 50.0 kg of gasoline when full, and the density of gasoline is 6.8 × 10² kg/m³. We can find the volume occupied by the gasoline (volume of the tank).

50.0 kg × (1 m³/6.8 × 10² kg) = 0.074 m³

The volume of the rectangular tank is:

volume = width × length × depth

depth = volume / width × length

depth = 0.074 m³ / 0.500 m × 0.900 m

depth = 0.16 m

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3 years ago

An infinite plane lies in the yz-plane and it has a uniform surface charge density.

Allisa [31]

Answer:

<u>So the correct answer is letter e)</u>

Explanation:

The electric field of an infinite yz-plane with a uniform surface charge density (σ) is given by:

$E=\frac{\sigma }{2\epsilon_{0}}$

Where ε₀ is the electric permitivity.

<u>As we see, this electric field does not depend on distance, so the correct answer is letter e)</u>

I hope it helps you!

6 0

3 years ago

If a 50kg boulder is 100m off the ground and a 25 kg boulder is 100 m off the ground, which has a

Flauer [41]

Answer:

Explanation:

It 100 kg It think

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3 years ago

The device used to measure a masses of a body is kilogram . true or false

olga nikolaevna [1]

Answer: false

Explanation:

While kilograms are the unit used to measure body mass, the device used is a scale.

Hope it helps :)

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3 years ago

A proton moves perpendicular to a uniform magnetic field B with arrow at a speed of 2.40 107 m/s and experiences an acceleration

noname [10]

Answer:

0.00956770833 T

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

m = Mass of proton = $1.67\times 10^{-27}\ kg$

a = Acceleration = $2.2\times 10^{13}\ m/s^2$

v = Velocity = $2.4\times 10^{7}\ m/s$

Magnetic field is given by

$B=\dfrac{ma}{qv}\\\Rightarrow B=\dfrac{1.67\times 10^{-27}\times 2.2\times 10^{13}}{1.6\times 10^{-19}\times 2.4\times 10^{7}}\\\Rightarrow B=0.00956770833\ T$

The magnetic field is 0.00956770833 T

4 0

3 years ago