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joja [24]
3 years ago
11

The particles of a gas are packed tightly together.

Physics
2 answers:
finlep [7]3 years ago
4 0

Answer:

False

Explanation:

yKpoI14uk [10]3 years ago
4 0

Answer:

False, they are much loose than any of the other states of matter

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Answer:

The force of the nail pushing in the opposite direction

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3 years ago
Which statement about ammeters and voltmeters is true?
Morgarella [4.7K]
What are the staments
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What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.
valkas [14]
<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit.

This Law is originally expressed as follows:

T^{2}=\frac{4\pi^{2}}{GM}a^{3}   (1)

Where;

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

M=6.39(10)^{23}kg is the mass of Mars

a=3.4(10)^{6}m  is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}    (2)

T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}    (3)

T=\sqrt{11581157.44 s^{2}}    (4)

Finally:

T=3403.1099s=56.718min    This is the orbital period of a spacecraft in a low orbit near the surface of mars

6 0
3 years ago
By which of the following is Venus characterized?
Dmitry_Shevchenko [17]

Venus has a dense atmosphere of mostly carbon dioxide. <em>(D)</em>

A, B, and C are false statements.

5 0
3 years ago
show the trajectory of a body projected with an initial velocity vat an angle of departure thita is a paraboler​
Jobisdone [24]

Answer:

Let me look up a couple of things regarding this question.

Explanation:

Then I will get back to you.

5 0
3 years ago
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