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3 years ago

6

From the deepest to the surface, what are the parts of the earth's interior?

1 answer:

shepuryov [24]3 years ago

3 0

The answer is A: Core --> Mantle --> Crust.

Core: The earth's core is the center of the earth, which would ultimately be the deepest. The core is made up of alloy, which is a mixture of many medals, such as iron and nickel.

Mantle: The earth's mantle is the layer between the earths crust and core. Often made of silicate rocks.

Crust: The earth's crust is the outer-most of the three options. Usually made of up different types of rocks.

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Black holes are:

agasfer [191]

Answer to the question provided is A

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4 years ago

Read 2 more answers

Find the kinetic energy ofan electron that moves at half the speed of light to four significant digits.

Vlad1618 [11]

Answer:

Ke=electron kinetic energy= $10.24*10^{33} J$

Explanation:

The electron has a mass of $9.1*10^{-31} kg$

The speed of light in a vacuum is a universal constant with the value 299 792 458 m / s (186 282,397 miles / s), although it is usually close to $3*10^{8} \frac{m}{s}$

Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:

$K=\frac{1}{2} *m*v^{2}$ Equation(1)

K=kinetic energy (J)

m =mass of the body (kg)

v= speed of the body $(\frac{m}{s} )$

for this problem We replace in the equation (1)

$me=9.1*10^{-31} kg$ = electron mass

$ve=1.5*10^{8} \frac{m}{s}$ =Half the speed of light

=electron speed

We replace in the equation (1) :

$Ke=\frac{1}{2}*me*ve^{2}$

$Ke=\frac{1}{2} *9.1*10^{-31} *(1.5*10^{8} )^{2}$

$Ke=4.55*10^{-31} *(1.5)^{2} *(10^{8} )^{2}$

$Ke=10.24*10^{33} J$

The energy kinetic of the electron is $10.24*10^{33} Joules$

7 0

3 years ago

A point charge of magnitude q is at the center of a cube with sides of length L.a) What is the electric flux through each of the

agasfer [191]

<h2>The flux through each face is q/6ε₀ .</h2>

Explanation:

The charge q is placed at the center of the cube of side L

According to Gauss's law the flux through any closed surface is q/ε₀

here q is the charge enclosed .

In this case cube has the six faces . The flux through each face = q/6ε₀

In the second case The cube has the face with length L₁

The flux through each face = q/6ε₀

Thus flux through the cube does not depend upon the size of the cube .

3 0

3 years ago

1-D Kinematics, Constant Acceleration After falling a distance of 45.0 m from the top of a building, a box is landing on the top

Mrrafil [7]

Answer:

Explanation:

Given

Object fall from a height of $s=45\ m$

Considering initial velocity to be zero i.e. $u=0$

using

$v^2-u^2=2as$

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

$v^2-0=2(9.8)\cdot 45$

$v=29.69\ m/s\approx 29.7\ m/s$

(b)Average acceleration

After falling 45 m, object strike the car and comes to rest after covering a distance of 0.5 m

again using

$v'^2-u'^2=2as'$

here final velocity will be zero i.e. $v'=0$

initial velocity $u'=v$

$0-(29.7)^2=2\cdot a\cdot 0.5$

$a=-882.09\ m/s^2$

(c)time taken by it to stop

$v'=u'+a't$

$0=29.7-882.09\cdot t$

$t=0.034\ s$

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3 years ago

Questions 9 out of 20

torisob [31]

Answer:

B

Explanation:

5 0

3 years ago