All categories

3 years ago

From the deepest to the surface, what are the parts of the earth's interior?

Physics

1 answer:

shepuryov [24]3 years ago

3 0

The answer is A: Core --> Mantle --> Crust.

Core: The earth's core is the center of the earth, which would ultimately be the deepest. The core is made up of alloy, which is a mixture of many medals, such as iron and nickel.

Mantle: The earth's mantle is the layer between the earths crust and core. Often made of silicate rocks.

Crust: The earth's crust is the outer-most of the three options. Usually made of up different types of rocks.

You might be interested in

How do objects move under the influence of gravity?

Nady [450]

Under the influence of gravity, objects just move down to the earth.

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

4 0

3 years ago

A cat accelerates from rest to 10m/s when it sees a dog. This takes 2 seconds. What was the acceleration of the cat

Nookie1986 [14]

The formula is a= chance in velocity/time
A=10-0/2
A=10/2
A=5 m/s^2 (meters per second squared)

5 0

3 years ago

Read 2 more answers

A student sees a newspaper ad for an apartment that has 1330 square feet of floor space. How many square meters of area are ther

hichkok12 [17]

One square meter equals 10.7 feet.

$1330 ft^2 * \frac{1m}{10.7ft^2} = 123.561$

8 0

4 years ago

I<br> What are physical properties of matter?

mariarad [96]

Answer:

appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity

Explanation:

7 0

3 years ago

A civil engineer wishes to redesign the curved roadway in the example What is the Maximum Speed of the Car? in such a way that a

vlabodo [156]

Answer:

24.3 degrees

Explanation:

A car traveling in circular motion at linear speed v = 12.8 m/s around a circle of radius r = 37 m is subjected to a centripetal acceleration:

$a_c = \frac{v^2}{r} = \frac{12.8^2}{37} = 4.43 m/s^2$

Let α be the banked angle, as α > 0, the outward centripetal acceleration vector is split into 2 components, 1 parallel and the other perpendicular to the road. The one that is parallel has a magnitude of 4.43cosα and is the one that would make the car slip.

Similarly, gravitational acceleration g is split into 2 component, one parallel and the other perpendicular to the road surface. The one that is parallel has a magnitude of gsinα and is the one that keeps the car from slipping outward.

So $gsin\alpha = 4.43cos\alpha$

$\frac{sin\alpha}{cos\alpha} = \frac{4.43}{g} = \frac{4.43}{9.81} = 0.451$

$tan\alpha = 0.451$

$\alpha = tan^{-1}0.451 = 0.424 rad = 0.424*180/\pi \approx 24.3^0$

3 0

4 years ago