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Anastasy [175]
3 years ago
10

DOES ANYONE PLAY NITRO TYPE

Physics
2 answers:
N76 [4]3 years ago
4 0

Answer:

Yess I do

Explanation:

lbvjy [14]3 years ago
3 0

Answer:

yes I dooooooooooooooo

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In a neutral atom the number of electrons equals the number of what part of what other part
koban [17]

Protons

Explanation:

In a neutral atom, the number of electrons equals the number of protons in the atom.

  •  Electrons are the negatively charge particles in an atom
  • Protons carry positive charge.
  • Neutrons do not carry any charges.

Protons and neutrons are contained in the nucleus of an atom they determine the mass number of the atom.

In a neutral atom, the number of protons and electrons must be the same.

A charge atom called an ion is one that has lost or gained electrons.

Learn more:

Cations brainly.com/question/8698247

#learnwithBrainly

3 0
3 years ago
A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ
Marat540 [252]

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r   (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C /  0.20 m

P.E =  4584.9 J = Work done

3 0
3 years ago
Who was Georges Lemaitre and how did he contribute to the Big Bang theory?<br> (15 points)
Ivahew [28]
A Belgian Astronomer and Cosmotologist who formulated the modern Big Bang theory, which states that the universe began in a cataclysmic explosion of a small, primeval “super-atom”
7 0
3 years ago
Niobium metal becomes a superconductor when cooled below 9 K. Its superconductivity is destroyed when the surface magnetic field
morpeh [17]

To develop the problem it is necessary to apply the concepts related to Magnetic Field.

The magnetic field is defined as

B = \frac{\mu_0 I}{2\pi r}

Where,

\mu_0 = Permeability constant in free space

r = Radius

I = Current

Our values are given as,

B = 0.1T

d = 4.5mm

r = 2.25mm

If the maximum current that the wire can carry is I, then

B = \frac{\mu_0 2I}{4\pi r}

I = \frac{Br}{2\frac{\mu_0}{4\pi}}

I = \frac{(0.1T)(2.25*10^{-3}m)}{2(1*10^{-7}N/A^2)}}

I = 1125A

Therefore the maximum current is 1125A

4 0
3 years ago
.. A 15.0-kg fish swimming at 1.10 m&gt;s suddenly gobbles up a 4.50-kg fish that is initially stationary. Ignore any drag effec
stira [4]

Answer:

(a) 0.846 m/s

(b) 2.097J

Explanation:

Parameters given:

Mass of big fish, M = 15 kg

Mass of small fish, m = 4.5 kg

Initial speed of big fish, U = 1.1 m/s

Initial speed of small fish, u = 0 m/s (it is stationary)

(a) We apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

Since both fish have the same final speed, V, (the small fish is in the mouth of the big fish), we have:

MU + mu = (M + m)*V

(15 * 1.1) + (4.5 * 0) = ( 15 + 4.5) * V

16.5 = 19.5V

=> V = 16.5/19.5

V = 0.846 m/s

The speed of the large fish after the meal is 0.846 m/s.

(b) We need to find the change in Kinetic energy of the entire system to find the total mechanical energy dissipated.

Initial Kinetic energy:

KEini = (½ * M * U²) + (½ * m * u²)

KEini = (½ * 15 * 1.1²) + (½ * 4.5 * 0²)

KEini = 9.075 J

Final Kinetic Energy:

KEfin = (½ * M * V²) + (½ * m * V²)

KEfin = (½ * 15 * 0.846²) + (½ * 4.5 * 0.846²)

KEfin = 5.368 + 1.610 = 6.978 J

Change in kinetic energy will be:

KEfin - KEini = 9.075 - 6.978

ΔKE = 2.097 J

The energy dissipated in eating the meal is 2.097 J

5 0
3 years ago
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