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2 years ago

Why did the solution change from blue to yellow (what chemical reaction happened)

Chemistry

1 answer:

Bumek [7]2 years ago

6 0

Answer:

Then HCl was added making the acid more blue because it's a base 5. Why did the solution change from yellow to blue (what chemical reaction happened)? The KOH led to the solution becoming more acidic. ... The solution's color shifted left.

Explanation:

please give me brainlist and follow

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Why is a typical car battery in a car is filled with a solution of sulferic acid

Lesechka [4]

Answer:

Sulfuric acid has a higher density than water, which causes the acid formed at the plates during charging to flow downward and collect at the bottom of the battery.

8 0

3 years ago

If 50.75 g of a gas occupies 10.0 l at stp, 129.3 g of the gas will occupy __________ l at stp.

Rom4ik [11]

Use PV = mRT/M and solve for R. R = PVM/RT. Since you have the same gas under two sets of conditions then you can write
P1V1M1/m1T1 = P2V2M2/m2T2 
Since P, M and T are constant, the equation becomes 
V1/m1 = V2/m2 
Now plug in your values and solve for V2

6 0

3 years ago

Read 2 more answers

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

The final concentration of sodium anion = 0.1035 M

4 0

3 years ago

What are the reactants and products? Write a reaction equation and label the reactants and products.

djyliett [7]

Reactants are the substance that undergo a change in a chemical reaction while products are what is produced after a reaction. don't have time to write a reaction.

8 0

2 years ago

Read 2 more answers

The density of copper is listed as 8.94g/cm 3 . Two students each make three density determinations of samples of the substanc

amm1812

Answer:

Density of the copper = 8.94g/cm^3

Student A results = 7.3gm/cm^3 ,9.4 gm/cm^3 , 8.3gm/cm^3

Student B results = 8.4 gm/cm^3 , 8.8 gm/cm^3 , 8gm/cm^3

From the observations we conclude that

Student A's result is accurate but not precise as the trials noted are not close to each other.

Student B's result is accurate and precise as the trials noted are close to each other.

Mean density of student A = 7.3 + 9.4 + 8.3 /3 = 8.33gm/cm^3

Mean density of student B = 8.4 + 8.8 + 8 /3 = 8.4 gm/cm^3

both the densities of A and B are 0.5 away from the actual density.

5 0

3 years ago