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quester [9]
3 years ago
6

Sunlight is more spread out as you move away from the equator.

Chemistry
1 answer:
suter [353]3 years ago
3 0

Answer:

False.

Explanation:

<u>The given statement asserts a false claim because the equator is the region that receives maximum sunlight</u>. The equator is placed right below the sun and thus, it tends to receive the maximum radiation across the year. While the poles are the coldest regions of the Earth because due to Earth's titled axis, they receive very few sun rays for a certain time of the year. Thus, <u>if we move away from the equator, we are likely to receive less radiation from the sun as the sun keeps getting farther while moving away from the equator</u>.

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Trimix 10/50 is a gas mixture that contians 10% oxygen and 50% helium, and the rest is nitrogen. If a tank of trimix 10/50 has a
Marat540 [252]

Answer : The partial pressure of helium is, 1.815\times 10^4KPa

Solution : Given,

Molar mass of O_2 = 32 g/mole

Molar mass of helium = 4 g/mole

Molar mass of N_2 = 28 g/mole

Total pressure of gas = 2.07\times 10^4KPa

As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.

First we have to calculate the moles of oxygen, helium and nitrogen gas.

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{10g}{32g/mole}=0.3125moles

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{50g}{4g/mole}=12.5moles

\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{40g}{28g/mole}=1.428moles

Now we have to calculate the total number of moles of gas mixture.

\text{Total number of moles of gas}=\text{Moles of oxygen gas}+\text{Mole of helium gas}+\text{Moles of nitrogen gas}

\text{Total number of moles of gas}=0.3125+12.5+1.428=14.24moles

Now we have to calculate the moles fraction of helium gas.

\text{Mole fraction of He gas}=\frac{\text{Moles of He gas}}{\text{Total number of moles of gas}}=\frac{12.5}{14.25}=0.877

Now we have to calculate the partial pressure of helium.

p_{He}=X_{He}\times P_T

where,

p_{He} = partial pressure of helium

P_T = total pressure

X_{He} = mole fraction of helium

Now put all the given values in this formula, we get

p_{He}=(0.877)\times (2.07\times 10^4KPa)=1.815\times 10^4KPa

Therefore, the partial pressure of helium is, 1.815\times 10^4KPa

8 0
3 years ago
What is the ph value of water and salt?
Andreyy89
The ph value of water is 7 but a salt which is  derived from a weak acid will be less than 7 and a salt which is derived from a base will be above 7.

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3 years ago
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Answer:

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Explanation:

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AlladinOne [14]

Answer:

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4 0
3 years ago
A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume
pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure   = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol

amount of SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol

mole fraction of N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330

mole of fractionSF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669

PV = nRT

P of N_2 O = \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa

mole of SF_4=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa

Total pressure  = 39127.053 + 79126.36 = 118253.413 Pa

6 0
3 years ago
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