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Llana [10]
3 years ago
11

A geosynchronous satellite orbits Mars (mass = 6.42 x 1023 kg) once every Martian day, 88640 s. At what radius does it orbit?

Physics
1 answer:
Schach [20]3 years ago
4 0

Answer:

angular speed ω = 2PI / T rad/sec  

ω^2*r = M*G/r^2

r = ³√ M*G/ω^2 = ³√6.42*10^23*6.67*10^-11*88640^2/39.5 = 2.04*10^7 m

Explanation:

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¿Cuál es la masa de un objeto cuya masa es de 400 J y energía cinética de 107J?
Pachacha [2.7K]

Answer:

Mass, m = 125 kg

Explanation:

Let us assume that the question says, "What is the mass of an object whose velocity is 400 m/s and the kinetic energy of 10⁷ J.

The kinetic energy of an object is :

K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^7}{(400)^2}\\\\m=125\ kg

So, the mass of the object is 125 kg.

3 0
4 years ago
Which environmental change occurs quickly
never [62]
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3 years ago
If an object has a mass of 14 kg, what is it’s weight
Alex_Xolod [135]

Answer:

Weight = 137.2 kg.m/s^{2}

Explanation:

Given

mass of an object, m = 14 kg

Weight (W) is given by the formula:

W = mg , where m is mass of the object and g is acceleration due to gravity and the value is 9.8 m/s^{2}

Hence W = 14 kg x 9.8 m/s^{2}

                = 137.2 kg.m/s^{2}

3 0
3 years ago
A classification of metamorphic rocks would indicate whether they are____
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Its either letter a or c
6 0
3 years ago
I NEED HELP!!!!! PLEASE ANSWER! FIRST CORRECT ANSWER WILL GET BRAINLIEST AND I WILL FOLLOW YOU!
Naily [24]

Average speed = (total distance) / (time to cover the distance)

We know:

    Average speed = 65 km/hr
    Total distance = 1,000 km 
    Time to cover it = (Driving Time) + 4 hours.

so we can write:

          65 km/hr  =  (1,000 km) / (Driving Time + 4hr)

          (I'm going to start calling the driving time 'DT'.
           Notice that DT is a number with the units of 'hours'.)

Multiply each side by    (DT + 4hr)

           (65 km/hr) (DT + 4hr)  =  1,000 km   

Eliminate parentheses on the left side:

           (65·DT km  +  260 km)  =  1,000 km

Subtract  260km  from each side:

              65·DT km          =    740 km

Divide each side by 65 :

                DT   =   11.38 hours .

DT (Driving Time) is the time you spent actually driving.
You had to cover the complete 1,000 km in that time.
So while you were driving, you had to do it at a speed of

                  1,000 km / 11.38 hrs  =  87.8 km/hr .
__________________________________________

As long as we're already totally bored by this question,
let's work on it some more, and check my answer:

... Driving for 11.38 hours at a speed of 87.8 km/hr, you cover

                     (11.38 hr) x (87.8 km/hr)  =  999.164 km  (close enough to 1,000) .

So far, so good.  The distance is taken care of.

With the 4-hour stop, the total trip takes 4 more hours = 15.38 hours.
So the average speed is

                     (1,000 km) / (15.38 hr)  =   65.02 km/hr

                                                                Close enough to 65 km/hr.  yay !

6 0
4 years ago
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