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liubo4ka [24]
3 years ago
8

8: As a grade-school project, students construct a mobile representing some of the major food groups.

Physics
1 answer:
Airida [17]3 years ago
4 0

Answer:

m1=0.72kg m2=0.48kg m3=0.98

Explanation:

12*m1=18*m2, so 2*m1=3*m2

6*(m1+m2)=24*.03, so 2*m1+2*m2=2.4

so, 5*m2=2.4, m2=0.48 then, m1=0.72

(m1+m2+0.3+0.2)*18=31*m3

1.7*18=31*m3

m3=0.98

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How do matter and energy interact?
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Biology involves living systems that interact with each other and with the environment. Like chemical processes, biological processes involve the transfer or sharing of electrons among atoms and the interaction of atoms and molecules with electromagnetic energy.

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3 years ago
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A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0
sergey [27]

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=\frac{1}{2}m(v^2-u^2)

Using the formula

Work done, W=\frac{1}{2}(0.145)((25)^2-0)

Work done=\frac{1}{2}(0.145)(625)

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

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3 years ago
What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita
sesenic [268]

Answer:

60m/s

Explanation:

initial energy = final energy

g.p.e = k.e

k.e = 0.5 × mass × velocity²

g.p.e = 990000J as per Question

990000Nm = 0.5 × 550 × V²

V² = 3600

V = 60m/s

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3 years ago
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3 years ago
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A woman 5.5 ft walks at a rate of 6 ft/sec towards a street light that is 22 ft above the ground. At what rate is the length of
Soloha48 [4]

Answer:

The length of her shadow is changing at the rate  -2 m/s

Explanation:

Let the height oh the street light, h = 22 ft

Let the height of the woman, w = 5.5 ft

Horizontal distance to the street light = l

length of shadow = x

h/w = (l + x)/x

22/5.5 =  (l + x)/x

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x = 1/3 l

taking the derivative with respect to t of both sides

dx/dt = 1/3 dl/dt

dl/dt = -6 ft/sec ( since the woman is walking towards the street light, the value of l is decreasing with time)

dx/dt = 1/3 * (-6)

dx/dt = -2 m/s

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3 years ago
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