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storchak [24]
2 years ago
12

A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds. Wha

t is the acceleration? 0-13 m/s2 0-6 m/s2 0.6 m/s2 O 13 m/s2​
Physics
1 answer:
olga55 [171]2 years ago
3 0

Answer:

6m/s²

Explanation:

Given parameters:

Initial velocity  = 35m/s

Final velocity  = 65m/s

Time taken  = 5s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time taken;

   Acceleration  = \frac{Final velocity  - Initial velocity }{time}  

So;

 Acceleration   = \frac{65  - 35}{5}    = 6m/s²

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A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

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T = \mu\cdot v^{2}

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\rho = \dfrac{m}{V}

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m=\rho\cdot V

If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

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The density of steel = 8050 kg/m3

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V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

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