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AnnZ [28]
3 years ago
15

Help im being TIMED A batter hits two balls during practice. Ball A travels 10 meters, while ball B travels 12 meters. The batte

r decides to hit ball A with less force. How will this change the motion of ball B?
The motion of ball B will increase.
The motion of ball B will decrease.
The motion of ball B will stay the same.
The motion of ball B will become the same as ball A.
Chemistry
2 answers:
12345 [234]3 years ago
8 0

Answer:

The third one

The Motion of ball b will stay the same

hope this helps

Explanation:

mina [271]3 years ago
7 0

Answer:

c

Explanation:

The batter aint changing the force he is using while hitting Ball B. Therefore, Motion of ball b will stay the same :D

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According to the big bang theory, which statements are accurate about how the universe came to be? Check all that apply.
asambeis [7]

The term Big Bang defines that the Universe has expanded from the ancient hot and thick primary situation at some fixed time in the past.

Big Bang theory refers to the origin of the Universe. In the beginning, universe is very heavy and small hot ball of matter. It was a point no bigger than the head of a pin when all the things squished with each other and universe is expanded with huge explosion of energy. Due to expansion, it is cooled and results in the formation of Stars and galaxies. After sometime, atoms formed like helium and hydrogen.

Thus, statement (1), (3) and (4) is correct whereas statement (2) and (5) is incorrect.

7 0
3 years ago
Read 2 more answers
Nitric acid, a major industrial and laboratory acid, is produced commercially by the multi-step Ostwald process, which begins wi
Marizza181 [45]
  • Answer:  3.178 Kg of ammonia must be used to produce 7.839 kg of nitric acid and The equations are not balanced.  Explanation:  Ostwald process  is a multi-step for manufacturing Nitric Acid.  First, We must check if our equations are balanced or not, by checking the amount of each element before and after the arrow.  Step 1: NH3(g) + O2(g) ⟶ NO(g) + H2O(l)  Step 2: NO(g) + O2(g) ⟶ NO2(g)  Step 3: NO2(g) + H2O(l) ⟶ HNO3(l) + NO(g)  For example in Step 1, the amount of Hydrogen atoms are different on both sides. On left side we can count 3 hydrogen atoms while on the right side we can count only 2 hydrogen atoms. In the Step 2, the amount of Oxygen atoms are different on both sides too. On the Left side we can count 3 oxygen atoms while on the right side we can count only 2 oxygen atoms and in step 3 the amount of Nitrogen atoms are different on both sides too. On the left side we can count 1 nitrogen atom while on the right side we can count 2 nitrogen atoms.  So, Let´s balance equations by inspection, just adding coefficients to each compound, until the amount of atoms are equal on both sides.   Step 1: 4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)  Step 2: 2NO(g) + O2(g) ⟶ 2NO2(g)  Step 3: 3NO2(g) + H2O(l) ⟶ 2HNO3(l) + NO(g)   Second we gather the information what we are going to use in our calculations. Final Mass of HNO3 = 7,839Kg  and Molecular Weigth = 63,01g/mol  NH3  Molecular Weight= 17,031 g/mol  Third we start discoverying the amount of NH3 that reacted completed to generate 7,839Kg of HNO3, using the giving equation and its respective molecular weights.  7,839Kg  of HNO3  x 1000g / 1Kg x 1mol HNO3 / 63,01g HNO3 x 3mol NO2 / 2 mol HNO3 x 2 mol NO/ 2 mol NO2 x 4 mol NH3/4 mol NO x 17,031g NH3/1 mol NH3 x 1 Kg / 1000g= 3,178 Kg NH3   The amount of NH3 that is required to produce 7,839 Kg of HNO3 is 3,178 Kg NH3
7 0
4 years ago
Michael has a substance that he puts in Container 1. The substance has a volume of 5 cubic meters He then puts
xxMikexx [17]

Answer:

gas is the correct answer.

Explanation:

8 0
3 years ago
Compute Reaction Rates for All Seven Trials
jeka94

Answer : The reaction rate at 3^oC,24^oC,40^oC\text{ and }65^oC are 36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec

Solution : Given,

Mass of tablet = 1000 mg

Volume of water = 0.200 L

The given formula will be,

\text{Reaction rate}=\frac{\text{Mass of tablet}/\text{Volume of water}}{\text{Reaction time}}

Now we have to calculate the reaction rate at different temperatures and reaction time.

\text{Reaction rate at }3^oC=\frac{1000mg/0.200L}{138.5sec}=\frac{5000mg/L}{138.5sec}=36mg/L/sec

\text{Reaction rate at }24^oC=\frac{1000mg/0.200L}{34.2sec}=\frac{5000mg/L}{34.2sec}=142mg/L/sec

\text{Reaction rate at }40^oC=\frac{1000mg/0.200L}{26.3sec}=\frac{5000mg/L}{26.3sec}=190mg/L/sec

\text{Reaction rate at }65^oC=\frac{1000mg/0.200L}{14.2sec}=\frac{5000mg/L}{14.2sec}=352mg/L/sec

Therefore, the reaction rate at 3^oC,24^oC,40^oC\text{ and }65^oC are 36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec

7 0
4 years ago
Read 2 more answers
A solution of chloroform, CHCl3, and acetone, (CH3)2CO, exhibits a negative deviation from Raoult's law. This result implies tha
Gnoma [55]

The given question is incomplete. The complete question is as follows.

A solution of chloroform (CHCl_{3}) and acetone ((CH_{3})_{2}CO) exhibits a negative deviation from Raoult's law. This result implies that:

chloroform-chloroform interactions are stronger than chloroform-acetone interactions.

chloroform-chloroform interactions are weaker than chloroform-acetone interactions.

acetone-acetone interactions are stronger than chloroform-acetone interactions.

acetone-acetone interactions are weaker than chloroform-acetone interactions

chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.

Explanation:

It is known that when the forces between the particles of the mixture are stronger than the forces between the particles in the pure liquids then negative deviations from Raoult's law are observed.

Hence, when a solution of chloroform (CHCl_{3}) and Acetone ((CH_{3})_{2}CO) will exhibit a negative deviation from Roult's law.

Then, chloroform-chloroform interactions should be weaker than chloroform-acetone interactions and acetone-acetone interactions must be weaker than Chloroform-Acetone interactions.

thus, we can conclude that for the given situation  chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.

7 0
4 years ago
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