The west coast of the united states receives two high tides and two low tides of varying heights per day. Tidal pattern is mixed semidiurnal tidal cycle
Sun and moon exert force on the ocean due to tides moves through the ocean Tide are very long period waves whose motion is directed by the effect of moon and sun . Tides originate in the ocean and progress toward the coastlines where they appear as the regular rise and fall of the sea surface.
An area has a diurnal tidal cycle if it experiences one high and one low tide every lunar day. An area has a semidiurnal tidal cycle if it experiences two high and two low tides of approximately equal size every lunar day An area has a mixed semidiurnal tidal cycle if it experiences two high and two low tides of different size every lunar day.
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From that list, the <em>exponents</em> should be handled first.
Here's the memory device for the order of operations
that I often see here on Brainly. I didn't learn it this way,
but this is a good and handy thing to remember:
<em>P E M D A S</em>
It stands for the order in which operations should be performed
if you're working to simplify an expression that has several different
operations in it.
<em>P</em>arentheses
<em>E</em>xponents
<em>M</em>ultiplication
<em>D</em>ivision
<em>A</em>ddition
<em>S</em>ubtraction
Answer:
0.087976 Nm
Explanation:
The magnetic torque (τ) on a current-carrying loop in a magnetic field is given by;
τ = NIAB sinθ --------- (i)
Where;
N = number of turns of the loop
I = current in the loop
A = area of each of the turns
B = magnetic field
θ = angle the loop makes with the magnetic field
<em>From the question;</em>
N = 200
I = 4.0A
B = 0.70T
θ = 30°
A = π d² / 4 [d = diameter of the coil = 2.0cm = 0.02m]
A = π x 0.02² / 4 = 0.0003142m² [taking π = 3.142]
<em>Substitute these values into equation (i) as follows;</em>
τ = 200 x 4.0 x 0.0003142 x 0.70 sin30°
τ = 200 x 4.0 x 0.0003142 x 0.70 x 0.5
τ = 200 x 4.0 x 0.0003142 x 0.70
τ = 0.087976 Nm
Therefore, the torque on the coil is 0.087976 Nm
You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final² = (V)initial²+2a(dx)
Given:
a=0.500m/s²
dx=6.32 m
(V)intial=0m
(V)final= UNKNOWN
(V)final= 2.51396m/s