(Help would be greatly appreciated) What is the molarity of a solution made from 325.4g of AlCl3 with enough water to make 500.0
mL?
1. 4.88g
2. 4.88M
3. 2.440M
4. 2.44M
1 answer:
Answer:
4.88 M
Explanation:
M = number moles/Volume (L)
MM AlCl3 = 133.34 g/mol
Volume = 500 mL = 0.5 L
number moles = mass/MM = 325.4/133.34 = 2.44 moles AlCl3
M = 2.44/0.5 = 4.88 M
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