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Zinaida [17]
2 years ago
6

(Help would be greatly appreciated) What is the molarity of a solution made from 325.4g of AlCl3 with enough water to make 500.0

mL?
1. 4.88g
2. 4.88M
3. 2.440M
4. 2.44M
Chemistry
1 answer:
puteri [66]2 years ago
7 0

Answer:

4.88 M

Explanation:

M = number moles/Volume (L)

MM AlCl3 = 133.34 g/mol

Volume = 500 mL = 0.5 L

number moles = mass/MM = 325.4/133.34 = 2.44 moles AlCl3

M = 2.44/0.5 = 4.88 M

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I don't know what the options were but a material that is very likely going to be challenging to recognize under a microscope as a mixture is a homogeneous mixture. A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water!
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Match the labels to the
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For the first blank, that is the endoplasmic reticulum
For the second, it is lysosome
For the third blank, it is the cell membrane
For the fourth, sorry I don’t know this one
For the fifth, that is the vacuole
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For the seventh, that is Golgi body
And lastly the eighth, it is the nucleus
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Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
Which of the following could happen when infrared radiation is absorbed by a molecule ?
Leto [7]

Answer:

       E) Intramolecular bond angles change

Explanation:

Infrared Radiation:

IR is electromagnetic radiations. The wavelength i.e. 700nm to 1000 mm of infrared is longer than invisible light and Its frequency is lower than light, that's why it is invisible to light.

  • When IR radiation strike the molecule it absorbed by this molecule.
  • This radiation used to identify and study chemicals.
  • Infrared radiation interact with intra-bonds of the molecule.
  • Bonds in the molecules have vibrational translational and rotational movements
  • Due to these vibration, rotation and translation movement it absorb a radiation of specific frequency and wavelength
  • These movements of bond are very small and absorbs radiations of very low frequency
  • So when Infrared light or radiation absorbed the intra-bonds of the molecule get affected and angles of these bonds changes.
  • As the frequency of the absorbed radiation matches the frequency of the bond that vibrates.

So

The correct option is option E

       E) Intramolecular bond angles change

* Note:

it couldn't be option A as the frequency of IR is not enough to rotate a whole molecule

It Couldn't be option B as IR rations are electromagnetic radiation of longer wave length so it one can not see it with light so how it will glow a molecule

It also not could be the option C as for the excitation of electrons require much higher energy.

It also not the option D as nuclear magnetic spin is associated with nuclear magnetic radiation that are much different from IR.

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