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ohaa [14]
3 years ago
8

I need help again!!!!!! Due today!!!! NO LINK PLEASE

Physics
1 answer:
Elden [556K]3 years ago
4 0

Answer:

The Acceleration of the object = 6.4 m/s²

<u>Explanation:</u>

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

<u>To Find:</u>

Acceleration of the object (a) = ?

<u>Required solution:</u>

Frictional force opposing the motion (F₂) = 8 N

Here in this question we have to find Acceleration of the object. So, firstly we have to find Net force of block after that we will find Acceleration of the object on the basis of conditions given above

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Now, we have to two elements that used in formula, Net force and Mass of block.

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

And we have to find Acceleration of the object.

We can find Acceleration of the object by using the Second law of Newton which says F = ma

Here,

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

So let's find Acceleration (a) !

† From second law of Newton

⇛ F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²

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A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
adell [148]

Answer:

A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of 36.9 ∘ above the horizontal. The monitor's speed is a constant 2.30 cm/s.

how much work is done on the monitor by (a) friction, (b) gravity

work(friction) = 453.5J

work(gravity) = -453.5J

Explanation:

Given that,

mass = 14kg

displacement length = 5.50m

displacement angle = 36.9°

velocity = 2.30cm/s

F = ma

work(friction) = mgsinθ .displacement

                      = (14) (9.81) (5.5sin36.9°)

                       = 453.5J

work(gravity)

= the influence of gravity oppose the motion of the box and can be pushing down, on the box from and angle of (36.9° + 90°)

= 126.9°

work(gravity) = (14) (9.81) (5.5cos126.9°)

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What is the magnitude momentum of a 2 kg body that moves with a speed of 3 m/s? (1 point)
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Answer:

<h2>D</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 2 kg

velocity/speed = 3 m/s

We have

momentum = 2 × 3 = 6

We have the final answer as

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The word/prefix "kilo" means one thousad

Good luck on your assignment and enjoy your day!

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