- Initial velocity=u=4.24m/s
- Time=t=2.91s
- Acceleration=a=-1.76m/s^2
- Final velocity=v
Using 1st equation of kinematics




Both frequencies and amplitudes are needed to transfer energy through a water wave ..
Answer:
a)r' = 4 r
b)
Explanation:
Given that car is moving with uniform speed.
At the verge of sliding
Friction force = Force due to circular motion

So we can say that
-----1
Where is the coefficient of friction
r is the radius of circular path
V is the velocity of car
a)
if the car speed become double
It means that new speed of car =2V
lets tale new radius of circular path is r'
---------2
From equation 12 and 2 we cay that
r' = 4 r
It means that we have to increase radius 4 times to avoid sliding
b)
In the above expression there is no any terms of mass ,it means that sliding speed does not depends on the weight of car.
So the sliding speed will remain same.
The answer to your question is b
The problem involves the conversion of potential energy to kinetic energy as the object falls from rest. Energy is conserved, so the equation used is:
PEi + KEi = PEf + KEf
Since the object is falling from rest, the initial kinetic energy is zero. Also, since the object hits the ground at its final position, the final potential energy is zero. This leaves:
PEi = KEf
mgh = 1/2 mv^2
*cancel out mass on both sides of the equation
gh = 0.5v^2
v = sqrt(2gh) = sqrt(2*9.81*4.5) = 9.40 m/s --> final ans.