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gayaneshka [121]
3 years ago
10

Write the word equation for the breaking down of the hydrogenperoxide

Physics
2 answers:
Lilit [14]3 years ago
4 0
2 H2O2 ➡️ 2 H2O + O







....
Julli [10]3 years ago
3 0
The equation for this decomposition reaction is: 2 H2O2 → 2 H2O + O.
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The initial speed of a body is 4.24 m/s. What is its speed after 2.91 s if it accelerates uniformly at -1.76 m/s2
shutvik [7]
  • Initial velocity=u=4.24m/s
  • Time=t=2.91s
  • Acceleration=a=-1.76m/s^2
  • Final velocity=v

Using 1st equation of kinematics

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=4.24+2.91(-1.76)

\\ \sf\longmapsto v=|4.24-5.12|

\\ \sf\longmapsto v=0.8m/s

6 0
2 years ago
Question below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇
Jobisdone [24]
Both frequencies and amplitudes are needed to transfer energy through a water wave ..
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2 years ago
A car is traveling in a uniform circular motion on a section of road whose radius is r. The road is slippery, and the car is jus
Basile [38]

Answer:

a)r' = 4 r

b)V=\sqrt{\mu rg}  

Explanation:

Given that car is moving with uniform speed.

At the verge of sliding

Friction force = Force due to circular motion

\mu mg=\dfrac{mV^2}{r}

So we can say that

V=\sqrt{\mu rg}          -----1

Where is the coefficient of friction

r is the radius of circular path

V is the velocity of car

a)

if the car speed become double

It means that new speed of car =2V

lets tale new radius of circular path is r'

2V=\sqrt{\mu r'g}                ---------2

From equation 12 and 2 we cay that

r' = 4 r

It means that we have to increase radius 4 times to avoid sliding

b)

V=\sqrt{\mu rg}  

In the above expression there is no any terms of mass ,it means that sliding speed does not depends on the weight of car.

So the sliding speed will remain same.

V=\sqrt{\mu rg}  

4 0
3 years ago
In an elastic collision, the momentum is _____, and the mechanical energy is _____.
olga nikolaevna [1]
The answer to your question is b
6 0
3 years ago
A 2,100 kg car is lifted by a pulley. If the cable breaks at 4.50 m, what is the velocity of the car when it hits the ground
kirill [66]
The problem involves the conversion of potential energy to kinetic energy as the object falls from rest. Energy is conserved, so the equation used is:

PEi + KEi = PEf + KEf

Since the object is falling from rest, the initial kinetic energy is zero. Also, since the object hits the ground at its final position, the final potential energy is zero. This leaves:

PEi = KEf
mgh = 1/2 mv^2

*cancel out mass on both sides of the equation

gh = 0.5v^2
v = sqrt(2gh) = sqrt(2*9.81*4.5) = 9.40 m/s --> final ans.
4 0
3 years ago
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