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2 years ago

What constitutes a solar system?

1 answer:

3 0

The Solar System may be divided by its components into three major regions: the inner system, the near outer system, and the far outer system. The near outer system might also be referred to as the middle system.

Our solar system consists of our star, the Sun, and everything bound to it by gravity — the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus and Neptune, dwarf planets such as Pluto, dozens of moons and millions of asteroids, comets and meteoroids.
Goodluck my friend!!

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Can someone help me with this molar mass problem?[It’s the last one]

quester [9]

Answer:

$54.18 \times 10^{23} \ moles$ in 3 mole of $Al_2(SO_4)_3$

Explanation:

It is clear that in the given $1\ mole$ of $Al_2(SO_4)_3$ have $3\ ions$ of $SO_4^2^-$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Since 1 ion of anything is equivalent to $6.02\times10^{23} \ moles$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Which is equivalent to $9 \times6.02\times10^{23}=54.18\times10^{23} \ moles$

Thus 3 moles of $Al_2(SO_4)_3$ gives $54.18\times10^{23} \ moles$ of $SO_4^2^-$ .

5 0

3 years ago

Consider the reaction given below.

Drupady [299]

Answer:

K = 0.167 s⁻¹

Explanation:

1) Rate law, at a given temperature:

Since all the data are obtained at the same temperature, the equilibrium constant is the same.

Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

r = K [A]ᵃ [B]ᵇ

2) Use the data from the table

Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

Use the first and second set of data to find the exponent a:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

2ᵃ = 2 ⇒ a = 1

3) Write the rate law

r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

4) Use any set of data to find K

With the first set of data

r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K = 0.167 s⁻¹

6 0

3 years ago

Determine the percent composition by mass of a 100g salt solution which contains 20g salt

prisoha [69]

Answer:

Mass of solution=100g

mass of salt=20g

so; mass of solute=80g

percentage composition =(mass of salt/total

mass) ×100

= \frac{20}{100} \times 100 \\ = 20\%

glad to help you

hope it helps

8 0

2 years ago

Read 2 more answers

For the reaction H₂O(g) + Cl₂O(g) → 2HClO(g), you know ΔS°rxn and S° of HClO(g) and of H₂O(g). Write an expression that can be u

expeople1 [14]

The expression for S°(Cl2O)(g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Given ,

The balanced chemical equation is ,

H2O (g) + Cl2O (g) → 2HClO (g)

The general standard entropy of the reaction is given by ,

ΔS°rxn = sum of the S°(Product ) - sum of the S°(reactants )

ΔS°rxn = ΣmS°products - ΣnS°reactants

where , m and n are the stoichiometry coefficients of each product and reactants .

Thus , the standard entropy of the given reaction is given by ,

ΔS°rxn = 2×S° (HClO)(g) - [ S°(H2O)(g) + S°(Cl2O)(g) ]

ΔS°rxn = 2×S° (HClO)(g) - S°(H2O)(g) - S°(Cl2O)(g)

Thus the S°(Cl2O) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Hence the expression for the standard entropy of Cl2O (g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

6 0

1 year ago

About one hundred thousand years ago, very fluid lava started erupting slowly and gently from a place near a plate boundary. Wha

victus00 [196]

a is the answer because all of the other answers are wrtong

3 0

3 years ago