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MrMuchimi
3 years ago
10

Proton traveling across a capacitor A proton enters with a velocity v between the plates of a capacitor as shown in the figure.

What is the direction of the magnetic field needed so that the proton continues its trajectory, undeflected? Explain each step of your reasoning.
Physics
1 answer:
yulyashka [42]3 years ago
3 0

Answer:

Please see the direction of force in the attachment

Explanation:

As the particle enters the capacitor, it experiences electric. In order to move in the same direction as the electron was moving before entering the capacitor, the force due to the electric field of capacitor must be balanced by the magnetic field.

The direction of particle is shown in the attachment.

As we know,

Force = q (v *B)

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Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawate
LenKa [72]

Answer:

12.64968 Hz

Explanation:

v = Velocity of sound in seawater = 1522 m/s

u = Velocity of dolphin = 7.2 m/s

f' = Actual frequency = 2674 Hz

From Doppler effect we get the relation

f=f'\frac{v-u}{v}\\\Rightarrow f=2674\frac{1522-7.2}{1522}\\\Rightarrow f=2661.35032\ Hz

The frequency that will be received is 2661.35032 Hz

The difference in the frequency will be

2674-2661.35032=12.64968\ Hz

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Volume is the space occupied by a quantity of matter. <br> a.true <br> b.false
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At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 fi
Amanda [17]

Answer:

Its approx location is (5.18,1.9)

Explanation:

Using F( 5,2) = ( xy-1, y²-11)

= ( 5*2-¹, 2²-11)

= (9,-5)

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(5,2)+(1.02-1)*(9,-5)

(5,2)+( 0.02)*(9,-5)

(5+0.18, 2-0.1)

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3 years ago
A plane flies from base camp to lake a, 200 km away in the direction 20.0° north of east. after dropping off supplies it flies t
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Distance of lake a is 200 km at 20 degree north of east

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now the distance between base and lake b is given as

d = d_1 + d_2

given that

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d_1 = 187.94 i + 68.4 j

d_2 = -230 sin30 i + 230 cos30 j

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now the total distance is

d = (187.94 - 115)i + (199.2 + 68.4)j

d = 72.94 i + 267.6 j

now the magnitude of the distance is given as

d = \sqrt{72.94^2 + 267.6^2}

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also the direction is given as

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8 0
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