Answer:
8.235 kg
Explanation:
Mass of the cylinder = 4.8 kg
The capacity (volume) of the cylinder = 50 liters
As 1 m^3 = 1000 liters
So, the volume of the cylinder, v= 0.05 m^3
The volume of filled nitrogen, v= 0.05 m^3
Pressure of filled nitrogen, p = 60 atm = 60\times 101325 Pa
Assuming that the nitrogen gas is at room temperature which is 25-degree centigrade,
So, the temperature of nitrogen gas, T=273+25= 298 K
By using the ideal gas equation, pv=nRT
Where n is the number of moles, R is the universal gas constant, R = 8.314 J/mol·K
Putting all the values in the ideal gas equation, we have
(60 x 101325)0.05 = n (8.314) x (298)
n= (60 x 101325 x 0.05)/(8.314 x 298)
n=122.69 moles
As the molar mass of nitrogen is 28, so the total mass of the nitrogen in the cylinder, m= 122.69 x 28 = 3435.32 grams = 3.435 kg.
Hence, the new mass of the cylinder = 4.8+3.435=8.235 kg
