The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be ____ and are
2 answers:
Answer: The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.
Explanation:
Chemical compounds that have conjugated planar ring systems where there are delocalized pi-electron clouds are present in place of individual alternate and single bonds.
This means that electrons present in a double bond of alkene are in conjugation.
Therefore, we can conclude that the double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.
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Answer:
Therefore the density of the sheet of iridium is 22.73 g/cm³.
Explanation:
Given, the dimension of the sheet is 3.12 cm by 5.21 cm.
Mass: The mass of an object can't change with respect to position.
The S.I unit of mass is Kg.
Weight of an object is product of mass of the object and the gravity of that place.
Density: The density of an object is the ratio of mass of the object and volume of the object.
[S.I unit of mass= Kg and S.I unit of m³]
Therefore the S.I unit of density = Kg/m³
Therefore the C.G.S unit of density=g/cm³
The area of the sheet is = length × breadth
=(3.12×5.21) cm²
=16.2552 cm²
Again given that the thickness of the sheet is 2.360 mm =0.2360 cm
Therefore the volume of the sheet is =(16.2552 cm²×0.2360 cm)
=3.8362272 cm³
Given that the mass of the sheet of iridium is 87.2 g.
=22.73 g/cm³
Therefore the density of the sheet of iridium is 22.73 g/cm³.