Answer:
Together, the number of protons and the number of neutrons determine an element's mass number. Since an element's isotopes have slightly different mass numbers, the atomic mass is calculated by obtaining the mean of the mass numbers for its isotopes.
Answer:
3.1 * 10^-14
Explanation:
Note that E°cell = 0.0592/n log K
We can obtain E°cell from the standard reduction potentials of cadmium and hydrogen
Anode reaction
H2(g) ----> 2H+ + 2e
Cathode reaction
Cd^2+(aq) + 2e -----> Cd(s)
E°cell = E°cathode - E°anode
E°cathode = –0.40 V
E°anode = 0 V
E°cell = –0.40 V - 0 V
E°cell = –0.40 V
E°cell = 0.0592/n log K
Where n=2 electrons transferred
–0.40 = 0.0592/2 log K
–0.40 = 0.0296 log K
log K = –0.40/0.0296
log K = -13.5135
K = Antilog ( -13.5135)
K = 3.1 * 10^-14
Answer:
ΔG ≅ 199.91 kJ
Explanation:
Consider the reaction:
temperature = 298.15K
pressure = 22.20 mmHg
From, The standard Thermodynamic Tables; the following data were obtained
The equilibrium constant determined from the partial pressure denoted as can be expressed as :
= 0.045
where;
R = gas constant = 8.314 × 10⁻³ kJ
199.912952 kJ
ΔG ≅ 199.91 kJ
Answer:
Max. work done in 60 g of copper plated out is 200472.14 J
Explanation:
Given cell reaction is:
Standard reduction potential of Zn electrode () is 0.763 V.
Standard reduction potential of Cu electrode () is -0.337 V.
Copper acts as cathode and Zinc acts as anode.
Cell potential (E) = E° cathode - E° anode
= 0.763 - (-0.337)
= 1.10 V
formula for the work done is as follows:
Here, n is no. of electron involved in the reaction.
F(Faraday's constant) = 96500
In the given reaction, n = 2
Therefore, 212300 J work is done by reducting 1 mol of copper.
Copper given is 60 g.
Molecular mass of copper is 63.54 g/mol.
Max. work done in 60 g of copper plated out is:
manganese The metal that is used as a sacrificial electrode to prevent the rusting of iron is manganese.