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sergejj [24]
3 years ago
11

The table shows the mechanical energy and velocity of a rock that was thrown four times. The rock has a mass of 2.4 kg.

Physics
2 answers:
Afina-wow [57]3 years ago
5 0
The second problem is b
ICE Princess25 [194]3 years ago
4 0

In each case we will find the Kinetic energy and find its difference with total mechanical energy

As we know that

Potential Energy = Mechanical Energy - Kinetic Energy

so if object will have more potential energy then it will have more height

now for potential energy in each case

1. Kinetic energy is given as

KE = \frac{1}{2} (2.4) 7^2 = 58.8 J

now PE = 32 - 58.8 = -26.8 J[/tex]

2. Kinetic energy is given as

KE = \frac{1}{2} (2.4) 2^2 = 4.8 J

now PE = 34 - 4.8 = 29.2 J[/tex]

3. Kinetic energy is given as

KE = \frac{1}{2} (2.4) 6^2 = 43.2 J

now PE = 35 - 43.2 = -8.2 J[/tex]

4. Kinetic energy is given as

KE = \frac{1}{2} (2.4) 3^2 = 10.8 J

now PE = 31 - 10.8 = 20.2 J[/tex]

So here maximum potential energy in case 2

So maximum height will be in case 2

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Answer:

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Explanation:

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3 years ago
Jane starts from her house to take a stroll in her neighborhood. After walking for 2 hours at a steady pace, she has walked 4 mi
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4 years ago
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The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota
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Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

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3 years ago
Captain John Stapp is often referred to as the "fastest man on Earth." In the late 1940s and early 1950s, Stapp ran the U.S. Air
valentina_108 [34]

Answer:

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Explanation:

The relationship between velocities and time is described by this equation: v_f=v_0+a*t, where v_f is the final velocity, v_0 is the initial velocity, a the acceleration, and t is the time during such acceleration is applied.

Solving the equation for the time, and applying to the case: t=\frac{v_f-v_0}{a}=\frac{0\frac{m}{s}-282\frac{m}{s}  }{-201\frac{m}{s^2} }=1.40s, where v_f=0\frac{m}{s} because the sled is totally stopped, v_0=282\frac{m}{s} is the velocity of the sled before braking and, a=-201\frac{m}{s^2} is negative because the deceleration applied by the brakes.

In the other hand, the equation that describes the distance in term of velocities and acceleration:x_f-x_0=v_0*t+\frac{1}{2}*a*t^2, where x_f-x_0 is the distance traveled, v_0 is the initial velocity, t the time of the process and, a is the acceleration of the process.

Then for this case the relationship becomes: x_f-x_0=282\frac{m}{s} *1.40s+\frac{1}{2}(-201\frac{m}{s})*(1.40s)^2=94.22m.

<u>Note that the acceleration is negative because is a braking process.</u>

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