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3 years ago

Please help me lol :|

Physics

1 answer:

Bogdan [553]3 years ago

6 0

Answer:

1 is community 2 habitat 4 producer 5 consumer 6 food chain 7 predator 8 prey sorry I don't know 4

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If you were to stand in the exact center of a rotating disc, you would only have what kind of

Dmitriy789 [7]

Answer:

Tangential speed or Rotational speed

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3 years ago

A 20 N south magnetic force pushes a charged particle traveling with a velocity of 4 m/s west through a 5 T magnetic field point

PtichkaEL [24]

Answer:

Charge of the particle is 1 coulomb.

Explanation:

Force, F:

${ \bf{F=BeV}}$

F is magnetic force.

B is the magnetic flux density.

e is the charge of the particle.

V is the velocity

${ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}$

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3 years ago

What does Force Means

zubka84 [21]

Answer:

strength or energy as an attribute of physical action or movement.

Explanation:

coercion or compulsion, especially with the use or threat of violence.

this is from google

3 0

3 years ago

Read 2 more answers

Suppose that a comet that was seen in 550 A.D. by Chinese astronomers was spotted again in year 1941. Assume the time between ob

pickupchik [31]

To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.

Kepler's third law tells us that

$T^2 = \frac{4\pi^2}{GM}a^3$

Where

T= Period

G= Gravitational constant

M = Mass of the sun

a= The semimajor axis of the comet's orbit

The period in years would be given by

$T= 1941-550\\T= 1391y(\frac{31536000s}{1y})\\T=4.3866*10^{10}s$

PART A) Replacing the values to find a, we have

$a^3= \frac{T^2 GM}{4\pi^2}$

$a^3 = \frac{(4.3866*10^{10})^2(6.67*10^{-11})(1.989*10^{30})}{4\pi^2}$

$a^3 = 6.46632*10^{39}$

$a = 1.86303*10^{13}m$

Therefore the semimajor axis is $1.86303*10^{13}m$

PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by

$R = a(1-e)$

$R = 1.86303*10^{13}(1-0.997)$

$R= 5.58*10^{10}m$

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3 years ago

ANSWER QUICKLY IN LESS THAN A MINUTE!!EASY!

luda_lava [24]

Answer:

I think it's 0 N 3rd choice

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2 years ago