Ribosomes create RNA, which are used as templates for making proteins
Answer:
1.047 M
Explanation:
The given reaction:
For dichromate :
Molarity = 0.254 M
Volume = 15.8 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 15.8 ×10⁻³ L
Thus, moles of dichromate :
Moles of dichromate = 0.0040132 moles
1 mole of dichromate react with 6 moles of iron(II) solution
Thus,
0.0040132 moles of dichromate react with 6 × 0.0040132 moles of iron(II) solution
Moles of iron(II) solution = 0.02408 moles
Volume = 23 mL = 0.023 L
Considering:
<u>Molarity = 0.02408 / 0.023 = 1.047 M</u>
Mass of Nd₂(SO₄)₃ : 2.653 g
<h3>Further explanation</h3>
Reaction
Nd₂Fe₁₄B + 17H₂SO₄ → Nd₂(SO₄)₃ + 14FeSO₄ + B + 17H₂
5 g Nd₂Fe₁₄B
MW = 2. 144,242 + 14. 55.845 + 10.811
MW = 288.484 + 781.83+10.811=1081.125 g/mol
mol :
mol Nd₂Fe₁₄B = mol Nd₂(SO₄)₃=0.0046
so mass of Nd₂(SO₄)₃ :
MW Nd₂(SO₄)₃ = 2.144.242+3.32,065+12.15,999
MW = 288.484+96.195+191.988=576.667 g/mol
Mgf is your answer to the question