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FromTheMoon [43]
3 years ago
12

Calculate the standard free energy for the following reaction at 25°C.

Chemistry
1 answer:
sladkih [1.3K]3 years ago
3 0
I dont think with this much amount of information we can solve this...unless its an reversible reaction in that case free energy =0
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When 0.40 mol Al is mixed with 0.40 mol Br2, the following reaction occurs: 2Al(s) + 3Br2(l) → 2AlBr3(s) Identify the limiting r
Lera25 [3.4K]

Answer:

d. The limiting reactant is Br2, and 0.13 mol Al should remain unreacted.

Explanation:

From the reaction, 2Al(s) + 3Br2(l) → 2AlBr3(s)

2 moles of Al combines with 3 moles of Br to form 2 moles of AlBr3

Hence 1 mole of Br combines with 2/3 moles of Al

or 0.4 moles of Br combines with 2/3×0.4 moles of Al or 0.267 Moles of Al leaving

0.4 - 0.267 = 0.133 moles of Al remaining unreacted

7 0
3 years ago
If a laser light is compose of photons each with an energy of 4.58 × 10−19 J, what is the photon energy of this light in units o
kap26 [50]

Answer : The photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

Solution :

Formula used :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = 4.58\times 10^{-19}J

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Now put all the given values in the above formula, we get:

4.58\times 10^{-19}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}

\lambda=4.3017\times 10^{-7}m=434.017\times 10^{-9}m=434.017nm=4.34\times 10^{-2}nm

conversion used : (1nm=1\times 10^{-9}m)

Therefore, the photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

5 0
3 years ago
What is the electronic configuration of the atom x​
Fofino [41]

Answer: K L M. 2 8 6.

Explanation:

6 0
3 years ago
Which groups on the periodic table contain metalloids?
Firlakuza [10]
Groups 13-16, hope this helps!
4 0
4 years ago
Read 2 more answers
PLS HELP!!!
Aleksandr-060686 [28]

Answer:

Physical Change. Physical changes are changes in which no bonds are broken or formed. This means that the same types of compounds or elements that were there at the beginning of the change are there at the end of the change.

7 0
3 years ago
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