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3 years ago

I NEED HELP ITS AN ECON QUESTION THE PICTURE IS ABOVE IF YOUR CORRECT I WILL GIVE YOU THE EXTRA POINTS APPRECIATE THE HELP

Physics

1 answer:

tester [92]3 years ago

3 0

Answer:

choose to spend limited resources to meet their needs

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9. An object starting with a velocity of 20m/s accelerates to

Aliun [14]

Answer:

6.25 s

Explanation:

V=u+at

t= (v-u)/a

= (45-20)/4 = 6.25 s

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3 years ago

Pls help asap asap asap aaaaaaa

Goryan [66]

Bro the picture is too dark I can’t see do it again so I can help you

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2 years ago

A grating has 470 lines/mm. how many orders of the visible wavelength 538 nm can it produce in addition to the m = 0 order?

Natali [406]

Three complete orders on each side of the m=0 order can be produced in addition to the m=0 order.

The ruling separation is d=1/(470mm-1)

$= 2.1 \times 10 {}^{ - 3}mm$

Diffraction lines occurs at an angle θ such that dsin=mλ,when λ is the wavelength and m is an integer.

Notice that for a given order,the line associated with a long wavelength is produced at a greater angle than the line associated with shorter wavelength.

we take λ to be the longest wavelength in the visible spectrum (538nm) and find the greatest integer value of m such that θ is less than 90°.

That is,find the greater integer value of m for which mλ<d.

since,d/λ

$= 538 \times 10 {}^{ - 9} m/2.1 \times 10 {}^{ - 6}$

There are three complete orders on each side of the m=0 order.

The second and third orders overlap.

learn more about diffraction from here: brainly.com/question/28168352

#SPJ4

4 0

1 year ago

How long will it take to go 150 km [E] traveling at 50 km/hr?

pantera1 [17]

It will take 3 hours

7 0

3 years ago

Read 2 more answers

Suppose a light source is emitting red light at a wavelength of 700 nm and another light source is emitting ultraviolet light at

klasskru [66]

Answer:

b) twice the energy of each photon of the red light.

Explanation:

$\lambda$ = Wavelength

h = Planck's constant = $6.626\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

Energy of a photon is given by

$E=h\nu\\\Rightarrow E=h\dfrac{c}{\lambda}$

Let $\lambda_1$ = 700 nm

$\lambda_2=350\\\Rightarrow \lambda_2=\dfrac{\lambda_1}{2}$

For red light

$E_1=\dfrac{hc}{\lambda_1}$

For UV light

$E_2=\dfrac{hc}{\dfrac{\lambda_1}{2}}$

Dividing the equations

$\dfrac{E_1}{E_2}=\dfrac{\dfrac{hc}{\lambda_1}}{\dfrac{hc}{\dfrac{\lambda_1}{2}}}\\\Rightarrow \dfrac{E_1}{E_2}=\dfrac{1}{2}\\\Rightarrow E_2=2E_1$

Hence, the answer is b) twice the energy of each photon of the red light.

7 0

2 years ago

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