1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lyudmila [28]
3 years ago
9

A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.

Chemistry
1 answer:
timama [110]3 years ago
6 0

Answer:

P=3.33atm

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr

Next, we add them up to obtain the total moles:

n_T=0.981mol+0.654mol=1.635mol

Now, the total volume:

V_T=4.00L+8.00L=12.00L

Finally, the total pressure is computed by using the ideal gas equation:

P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm

Best regards!

You might be interested in
Consider the following reaction: 2CH3OH ---> 2CH4+O2 delta H= +252.8kJ. Calculate the amount of heat transferred when 22.0g o
nydimaria [60]
To calculate the amount of heat transferred when an amount of reactant is decomposed, we must look at the balanced reaction and its corresponding heat of reaction. In this case, we can see that 252.8 kJ of heat is transferred per 2 moles of CH3OH used. When 22 g of CH3OH is used, 86.9 kJ is absorbed. 
4 0
3 years ago
How many electrons should Nitrogen (N) have around its Lewis dot model?
Delvig [45]

Answer:

5

Explanation:

3 0
4 years ago
What is the mass of 3.04×10^-4 mol of baking soda, NaHCO3?​
Zigmanuir [339]

Answer:

0.025536g

Explanation:

no. of mole = mass/Mr

mass = Mr ×  no. of mole

         = [23 + 1 + 12 + 3(16)] × 3.04×10^-4

         = 0.025536g

         = 0.0255g (3 significant figures)

8 0
3 years ago
Calculate the mass in grams of 7.88 mol of RbMnO4
vitfil [10]
Molar mass RbMnO₄ = 204.40 g/mol

1 mole ---------- 204.40 g
7.88 mole ------ ?

mass = 7.88 * 204.40 / 1

mass = 1610.672 g

hope this helps!
8 0
3 years ago
Two liquids- one polar, one nonpolar- have the same molar mass. Which one has the higher boiling point?
victus00 [196]

Answer:

D. the polar liquid will have the higher boiling point, since its molecules have dipole-dipole interactions.

Explanation:

<em>Dipole-Dipole interactions</em> take place only between polar molecules.

They consist of attractions between the negative end of a polar molecule and the positive end of another polar molecule. For example, between the O atom and the H atom in water.

These attractions are not present in a non-polar liquid, so its molecules will be more loosely held together and its boiling point will be lower.

8 0
3 years ago
Read 2 more answers
Other questions:
  • Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Comple
    5·1 answer
  • an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
    8·1 answer
  • When hydrogen chloride ionizes in water, which reactant is the proton donor? chlorine which reactant is the proton acceptor? hyd
    5·1 answer
  • How many grams are in 0.500 mol of Na (molar mass of Na = 22.99 g/mol)?
    15·1 answer
  • The mass of an atom is ________________________.
    14·2 answers
  • A small sack of sand has a density of 1.5 g/cm3 and a mass of 1500 g. How much space (volume) does the sand occupy? 750 cm3 2250
    15·2 answers
  • HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)
    13·2 answers
  • For #11 how to determine the signs?
    5·2 answers
  • HELP WILL GIVE BRAINLIEST!
    6·1 answer
  • Molecular formula of sulphur trioxide by criss cross method ​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!