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natta225 [31]
3 years ago
13

True or False:

Physics
2 answers:
viva [34]3 years ago
8 0

Answer:

True. The object's location is based off of the reference point, so by moving the reference point, you move the object's location.

Explanation:

pantera1 [17]3 years ago
3 0

Answer:

True

Explanation:

the reference point is where the object starts so changing where it starts changes the objects location.

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A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.75 104 m/s, and the radius of the or
Arisa [49]

Answer:

v = 1.32 10² m

Explanation:

In this case we are going to use the universal gravitation equation and Newton's second law

    F = G m M / r²

    F = m a

In this case the acceleration is centripetal

    a = v² / r

The force is given by the gravitational force

    G m M / r² = m v² / r

    G  M/r =  v²

Let's calculate the mass of the planet

    M = v² r / G

    M = (1.75 10⁴)² 5.00 10⁶ / 6.67 10⁻¹¹

    M = 2.30 10²¹ kg

With this die we clear the equation to find the orbit of the second satellite

    v = √ G M / r

    v = √ (6.67 10⁻¹¹ 2.30 10²¹ / 8.75 10⁶)

    v = 1.32 10² m

8 0
3 years ago
What is the evidence proving that we're in the 6th mass extinction?
Sveta_85 [38]

Answer:

Global warming and climate change

8 0
3 years ago
A stone is dropped from a cliff. after it has fallen 10m what is the stones velocity
Ludmilka [50]
The answer is 14,1421 m/s. :)
3 0
3 years ago
Read 2 more answers
A basketball is tossed up at an initial speed of 20 m/s.
qwelly [4]

Gravity slows the upward speed of any rising object by 9.8 m/s every second.

If the ball is tossed upward at 20 m/s, then it's at the top of its arc and its speed has dwindled to zero in (20/9.8) = 2.04 seconds.

During that time, its starting speed is 20 m/s and its ending speed is zero, so its AVERAGE speed all the way up is (1/2) (20 + 0)  =  10 m/s .

Sailing upward for 2.04 seconds at an average speed of 10 m/s, the ball rises to (2.04 x 10)  =  <em>20.4 meters.</em>

4 0
3 years ago
When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people
Tanzania [10]

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout \beta _{1}=58.4dB

When n number of person shout together \beta _{n}=102dB

The sound intensity level during one person shout is given by:

\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}

The sound intensity level during n number of person shout is given by:

\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}

Since each person generates same sound intensity and hence total number  of persons can be determined as

 =\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909

Hence

The number of people at game are approximately 22909

3 0
3 years ago
Read 2 more answers
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