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Nat2105 [25]
2 years ago
11

how many moles of sodium phosphate are required to make 7.5 moles of sodium nitrate in 2Na3PO4+3Be(NO3)=6NanO3+Be3(PO4)2

Chemistry
1 answer:
KIM [24]2 years ago
8 0

Answer:

<em>2.5</em> moles of sodium phosphate

Explanation:

3 Pb(NO3)2 + 2 Na3PO4 → Pb3(PO4)2 + 6 NaNO3

6 (moles in the reaction)- 7.5(moles  in the task)

2 (moles in the reaction)- x (moles in answer) ⇒6x = 2*7.5 ⇒ x = 15/6=2.5 (moles)

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Answer:

25.6g de HF son producidos

Explanation:

<em>...¿Cuánto HF es producido?</em>

Para resolver este problema debemos convertir la masa de cada reactivo a moles usando su masa molar. Como la reacción es 1:1, el reactivo con menor número de moles es el reactivo limitante. Con las moles del reactivo limitante podemos obtener las moles de HF y su masa así:

<em>Moles CaF2:</em>

Masa molar:

1Ca = 40g/mol

2F = 19*2 = 38g/mol

40+38 = 78g/mol

50g CaF2 * (1mol/78g) = 0.641 moles CaF2

<em>Moles H2SO4:</em>

Masa molar:

2H = 2g/mol

1S = 32g/mol

4O = 64g/mol

98g/mol

100g H2SO4 * (1mol / 98g) = 1.02 moles H2SO4

Como las moles de CaF2 < Moles H2SO4: CaF2 es reactivo limitante.

<em>Moles HF usando la reacción:</em>

0.641 moles CaF2 * (2mol HF / 1mol CaF2) = 1.282 moles HF

<em>Masa HF:</em>

Masa molar:

1g/mol + 19g/mol = 20g/mol

1.282 moles HF * (20g/mol) =

<h3>25.6g de HF son producidos</h3>
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3 years ago
What evidence in Side View lets you know that upwelling is happening in these locations?
mojhsa [17]

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Explanation:

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3 years ago
The cycle of copper reactions starts with solid copper metal and ends with solid copper metal. Suppose you start with 0.502 g of
Marianna [84]

Answer: percentage of the copper recovered is 88.8 %

Explanation:

Given : Initial amount of copper = 0.502 g

Recovered amount of copper = 0.446 g

percentage of copper recovered = \frac{\text {recovered amount}}{\text {initial amount}}\times 100\%

Putting in the values :

percentage of copper recovered = \frac{0.446}{0.502}\times 100\%=88.8\%

Thus percentage of the copper recovered is 88.8 %

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