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2 years ago

how many moles of sodium phosphate are required to make 7.5 moles of sodium nitrate in 2Na3PO4+3Be(NO3)=6NanO3+Be3(PO4)2

Chemistry

1 answer:

KIM [24]2 years ago

8 0

Answer:

<em>2.5</em> moles of sodium phosphate

Explanation:

3 Pb(NO3)2 + 2 Na3PO4 → Pb3(PO4)2 + 6 NaNO3

6 (moles in the reaction)- 7.5(moles in the task)

2 (moles in the reaction)- x (moles in answer) ⇒6x = 2*7.5 ⇒ x = 15/6=2.5 (moles)

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Which element has the LEAST metallic character.

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Helium would be the least I think

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Select the correct answer. Based on the reactivities of the elements involved, which reaction will form products that are more s

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Answer: The correct answer is option B.

Explanation: Reactivity of elements is defined as the tendency to loose or gain electrons.

These reactions are a type of single displacement reactions. A single displacement reaction is a type of reaction in which an element displaces another element in a chemical reaction. These are studied with the help of reactivity series.

The element which lies above in the reactivity series can easily displace the element which lies below in the reactivity series.

Option A: This reaction will not yield a stable product because Zinc lies below Aluminium in the reactivity series.

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Option D: This reaction will not yield a stable product because Calcium lies below Barium in the reactivity series.

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8 0

3 years ago

Chlorine pentafluoride gas is collected at -17.0 °C in an evacuated flask with measured volume of 35.0 L. When all the gas has b

Svet_ta [14]

Answer:

1. The mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of Chlorine pentafluoride, ClF5, is 0.3mole

Explanation:

1. To solve the mass of Chlorine pentafluoride, ClF5, first, let us calculate the molar mass of ClF5. This is illustrated below:

Molar Mass of ClF5 = 35.5 + (5 x 19) = 35.5 + 95 = 130.5g/mol

From the ideal gas equation:

PV = nRT (1)

Recall:

Number of mole(n) = mass (m) /Molar Mass(M)

n = m/M

Now substituting the value of n in equation 1, we have:

PV = nRT

PV = mRT/M

Now we can obtain the mass of Chlorine pentafluoride ClF5 as follow:

Data obtained from the question include:

T (temperature) = -17.0 °C = - 17 + 273 = 256K

V (volume) = 35L

P (pressure) = 0.180 atm

R (gas constant) = 0.082atm.L/Kmol

m (mass of Chlorine pentafluoride) =?

M (molar mass of Chlorine pentafluoride) = 130.5g/mol

PV = mRT/M

0.180 x 35 = m x 0.082 x 256/ 130.5

Cross multiply to express in linear form as shown below:

m x 0.082 x 256 = 0.180x35x130.5

Divide both side by 0.082 x 256

m = (0.180x35x130.5) /(0.082x256)

m = 39.16g

Therefore, the mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of ClF5 can be obtained as follow:

Mass of ClF5 = 39.16g

Molar Mass of ClF5 = 130.5g/mol

Mole of ClF5 =?

Number of mole = Mass /Molar Mass

Mole of ClF5 = 39.16/130.5g

Mole of ClF5 = 0.3mole

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Which of the following elements is a highly reactive nonmetal? A. iron (Fe) B. sodium (Na) C. flourine (F) D. helium (He)

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