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3 years ago

9

Draw a line graph showing the population of beetles and healthy trees in the forest for five years. Round the numbers to the nea

rest whole number.

2 answers:

Sergio [31]3 years ago

8 0

how do i draw a line ghraph on a computer

nikitadnepr [17]3 years ago

4 0

Answer:

Sample answer is the first one and my answer is the second

Their both the same just different ways

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The mass of proton<br>1) 1072* 10-28

jasenka [17]

Answer:

Mass of proton is

<h2>1.6726219 × 10-27 Kg</h2>

HOPE U UNDERSTOOD

MARK AS BRAINLIEST ONE

THANKS

IF ANY DOUBTS? PLS COMMENT

5 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0

3 years ago

What volume of a 1.5 M KOH solution is needed to provide 3.0 moles of KOH?

Brums [2.3K]

Answer:

Volume = <u>2.0 liter</u> of 1.5 M solution of KOH

Explanation:

<u>1) Data:</u>

a) Solution: KOH

b) M = 1.5 M

c) n = 3.0 mol

d) V = ?

<u>2) Formula:</u>

Molarity is a unit of concentration, defined as number of moles of solute per liter of solution:

M = n / V in liter

<u>3) Calculations:</u>

Solve for n: M = n / V ⇒ V = n / M

Substitute values: V = 3.0 mol / 1.5 M = 2.0 liter

You must use 2 significant figures in your answer: <u>2.0 liter.</u>

8 0

3 years ago

This is all the water; the liquid portion of the planet.

Dominik [7]

The oceanic part of the earth is the liquid portion Of the planet

6 0

3 years ago

the half of an oxidation-reduction reaction shows the iron gains. what does this electron gain mean for iron.

Nataly [62]

The correct answer is option C, that is, it is reduced.

In reduction and oxidation reactions, reduction refers to the loss of an oxygen atom from a molecule or the gaining of one or more electrons. A reduction reaction is observed from the perspective of the molecule being reduced, as when one molecule gets reduced, another one gets oxidized. The complete reaction is called a redox reaction.

In the given case, iron gains electrons mean that it is reduced.

3 0

3 years ago