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Monica [59]
3 years ago
15

Plz help due in 10 minutes will give brianlest to best answer

Physics
2 answers:
s344n2d4d5 [400]3 years ago
6 0

Answer:

Muscular Force - Uses when walking

The Force of wind - Force used to turn a windmill

Force of Gravity - Used to drag thing to the center  of the earth

Steam -  Type of force used to operate machines

Work -  Amount of force Times the distance moved

Foot - Pound - Moving one pound one foot

Newton meter - moving one newton one meter

Ahat [919]3 years ago
4 0

Answer:

Muscular Force = Uses when walking

The Force of wind = Force used to turn a windmill

Force of Gravity = Used to drag thing to the centre of the earth

Steam = Type of force used to operate machines

Work = Amount of force Times the distance moved

Foot - Pound = Moving one pound one foot

Newton meter = moving one newton one meter

Explanation:

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What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates
34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance C_{0} = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 \times 10^{4} V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

             V = Ed

Now,  

              Q = CV

or,           Q = C \times Ed

Therefore, substitute the values into the above formula as follows.

              Q = C \times Ed

                  = 8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})

                  = 2.55 \times 10^{-10} C

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is 2.55 \times 10^{-10} C.

3 0
3 years ago
WILL GIVE BRAINLIEST!
Ulleksa [173]

Answer:0kgm/s

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Momentum before collision=momentum after collision

Since the momentum of the two blocks have positive sign, it means they are moving in thesame direction

Therefore we use the formula

Momentum (A)+momentum (B)=Momentum (A)+momentum (B)

25+35=60+momentum (B)

60=60+momentum (B)

Momentum (B)=60-60

Momentum (B)=0kgm/s

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Check the attached file for the answer.

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Sort the following forces as relevant or not relevant to this situation. The symbols are defined as follows: normal force = n⃗ ,
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Answer:

it would be least to graetest

Explanation:

10-84

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