Answer:
Initial Velocity = 0 m/s
Final Velocity = 34.6 m/s
time = 3.5 s
Explanation:
The initial velocity must be zero since, the egg must be at rest initially, before dropping.
<u>Initial Velocity = 0 m/s</u>
Now, for time we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = Height = 61 m
Vi = Initial Velocity = 0 m/s
g = 9.8 m/s²
t =time = ?
Therefore,
61 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t² = (61 m)(2)/(9.8 m/s²)
t = √(12.45 s²)
<u>t = 3.5 s</u>
Now, for final velocity we will use 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.6 m/s
Answer:
Go in notifications, it'll show if it was answered. If it doesn't show that a person answered it, wait a while, someone might respond :)
Explanation:
On the Top right of your screen, theres a bell button. Click that and it will show all the notifications. it will also show if a person answered it.
It will pop up like
*random username* answered your question! ]
Hope this helped
Explanation:
PE= mgh
6 J= (3m) (9.81 m/s2) (mass)
mass=( 6)/(3×9.81)
mass= 0.20 Kg
I believe you are right! If the wheels were bigger then they would add more mobility to the wagon with less effort because Allowing it to take more weight (from the wagon) allowing you to pull much easier.
Have a blessed day!
Answer:
d = 8.4 cm
Explanation:
In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:
(1)
A: amplitude of the oscillation
w: angular speed of the oscillation = 2
f
f: frequency = 0.17Hz
The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:
Then, you solve for A in the equation (1) and replace the values of the parameters:
The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:
d = 2A = 2(4.2cm) = 8.4cm
