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ipn [44]
3 years ago
12

A car travels in 300 km in 3 hours. What can be determined?

Physics
1 answer:
bazaltina [42]3 years ago
7 0

Answer: If a car travels 300 km in 3 hours, then it’s speed will will be 100 km/hr. But in practical it depends upon type of car, condition of car, car's maximum speed and also the path in which car is travelling.. Because car can't travel in constant speed of 100 km/hr. So, if car have 120 km/hr as maximum speed than it's minimum speed will be 85–95 km/hr. And so the car travel 300 km in around 5 or 5 and half hours.

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Help pls i need this right now
pantera1 [17]

Answer:

The x-component of F_{3} is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O (1)

Where:

\vec F_{1}, \vec F_{2}, \vec F_{3} - External forces exerted on the ring, measured in newtons.

\vec O - Vector zero, measured in newtons.

If we know that \vec F_{1} = (70.711,70.711)\,[N], \vec F_{2} = (-126.859, 46.173)\,[N], F_{3} = (F_{3,x},F_{3,y}) and \vec O = (0,0)\,[N], then we construct the following system of linear equations:

\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N (2)

\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N (3)

The solution of this system is:

F_{3,x} = 56.148\,N, F_{3,y} = -116.884\,N

The x-component of F_{3} is 56.148 newtons.

5 0
2 years ago
if ur riding a bike uphill do you want the output force to be greater than the input force or does the output force have to be l
andrey2020 [161]

Answer: you want your input force harder

Explanation:

8 0
3 years ago
A ball is dropped off the roof of a tall building. If the ball reaches the ground in 8 seconds, how tall is the building, in met
Ghella [55]

Let <em>b</em> be the height of the building, and <em>y</em> the height of the ball at time <em>t</em>, given by

<em>y</em> = <em>b</em> - 1/2 <em>gt</em>²

where <em>g</em> = 9.8 m/s² is the magnitude of the acceleration due to gravity.

It takes the ball 8 s to reach the ground, at which point <em>y</em> = 0, so that

0 = <em>b</em> - 1/2 (9.8 m/s²) (8 s)²

<em>b</em> = 1/2 (9.8 m/s²) (8 s)²

<em>b</em> = 313.6 m

5 0
3 years ago
What’s the Answer for 5-8?
Dafna1 [17]

6. B. 4 electrons

7. Carbon is in everything and it's a compound that all organisms need

8. D. 3

9. Nitrogen gas is almost 80% of the atmosphere

10. Diatomic molecules compose 2 atoms

3 0
3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

3 0
2 years ago
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