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ipn [44]
3 years ago
12

A car travels in 300 km in 3 hours. What can be determined?

Physics
1 answer:
bazaltina [42]3 years ago
7 0

Answer: If a car travels 300 km in 3 hours, then it’s speed will will be 100 km/hr. But in practical it depends upon type of car, condition of car, car's maximum speed and also the path in which car is travelling.. Because car can't travel in constant speed of 100 km/hr. So, if car have 120 km/hr as maximum speed than it's minimum speed will be 85–95 km/hr. And so the car travel 300 km in around 5 or 5 and half hours.

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The correct  answer is A.

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5 0
3 years ago
1.a machine gun fires a ball with an initial velocity of 600m/s with an elevation of 30° with respect to the ground neglecting a
Sedbober [7]

Answer:

See explanation

Explanation:

a) maximum height of a projectile = u sin^2θ/2g

H= 600 × (sin 30)^2/2 × 10

H= 7.5 m

b) Time of flight

t= 2u sinθ/g

t= 2 × 600 sin 30/10

t= 60 seconds

Range

R= u^2sin2θ/g

R= (600)^2 × sin2(30)/10

R= 31.2 m

3 0
3 years ago
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5 0
3 years ago
We know the frequency range of certain sounds are: 400-560 Hz, what are the ranges of wavelength in meters when the signal trans
Ksivusya [100]

Answer:

Range of wavelength will be 5.35\times 10^5m to 7.5\times 10^5m

Explanation:

We have given range of frequency is 400-560 Hz

Speed of the light c=3\times 10^8m/sec

We have to find the range of the wavelength of signal transmitted

Ween know that velocity is given by v=\lambda f, here \lambda is wavelength and f is frequency

So for 400 Hz frequency wavelength will be \lambda =\frac{c}{f}=\frac{3\times 10^8}{400}=7.5\times 10^5m

And wavelength for frequency 560 Hz \lambda =\frac{c}{f}=\frac{3\times 10^8}{560}=5.35\times 10^5m

So range of wavelength will be 5.35\times 10^5m to 7.5\times 10^5m

8 0
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Bad White [126]
D. Because the moons shadow during a total lunar eclipse is tinnier than the earth.
8 0
3 years ago
Read 2 more answers
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