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ipn [44]
3 years ago
12

A car travels in 300 km in 3 hours. What can be determined?

Physics
1 answer:
bazaltina [42]3 years ago
7 0

Answer: If a car travels 300 km in 3 hours, then it’s speed will will be 100 km/hr. But in practical it depends upon type of car, condition of car, car's maximum speed and also the path in which car is travelling.. Because car can't travel in constant speed of 100 km/hr. So, if car have 120 km/hr as maximum speed than it's minimum speed will be 85–95 km/hr. And so the car travel 300 km in around 5 or 5 and half hours.

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What is the volume of an object that has Mass=100g and Density= 745g/mL.
lana66690 [7]

Answer:0.13ml

Explanation:

6 0
3 years ago
What are two ways of changing PE?
Anna35 [415]
Potential energy is simply energy that can be but isn't yet 
it can also be changed by putting it into motion or setting it off by using force or enacting gravity by dropping it.
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3 years ago
All neutron stars are things that produce intense gravity. All neutron stars are extremely dense objects. Therefore, all extreme
nika2105 [10]

Answer:

Major term is 'things that provide intense gravity'

Minor term is 'extremely dense objects'

Middle term is 'neutron stars'

Explanation:

  • Major term is given by the predicate part of the conclusion
  • Minor term is given by the subject part of sentence in conclusion
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6 0
4 years ago
Will give 45 points to who ever solves this
Lubov Fominskaja [6]

Answer:

1.  230 kg...

W = m * g

W= 230 kg  * 9.81 m/s^2

<u>W=  2256,3 N</u>

     m= 230kg ,   W = 2256,3 N , g= 9.81 m/s^2

2.  887 N

W= m * g

887 N = m * 9.81 m/s^2

<u>m= 90,42 kg</u>

     m= 90,42 kg,  W = 887 N ,  g= 9.81 m/s^2

3.  420 kg

W= m * a

w= 420 kg *  9.81 m/s^2

<u>w=</u><u>  </u><u>4120,2 N</u>

     m=  420 kg , W = 4120,2 N , g= 9.81 m/s^2

4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.

w = m * g

55.5 N = 15 kg * g

<u>a=  3,7 m/s^2</u>

     m = 15 kg , W= 55.5 N , g=  3,7 m/s^2

7 0
2 years ago
Read 2 more answers
A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4
bija089 [108]

Answer:

   w = 0.55 rad / s

Explanation:

For this exercise let's use the conservation of angular momentum, let's write the moment in two moments

Initial

    L₀ = r p + 0

    L₀ = r mv

The first term is the angular momentum of the mass

Final

      Lf = (I + m r²) w

Where I is the moment of inertia of the stool and the other term is the moment of inertia of the mass

      L₀ = Lf

      r mv = (I + m r²) w

      w = m r v / (I + m r²)

Let's calculate

      w = 2.0 0.45 3.0 / (4.5 + 2.0 0.45²)

      w = 2.7 / 4.9

     w = 0.55 rad / s

4 0
4 years ago
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