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Shtirlitz [24]
3 years ago
9

1. A _____ is applied to a wall or roof rafters to add strength and keep the building straight and plumb.

Engineering
1 answer:
PSYCHO15rus [73]3 years ago
7 0

Answer:

A force must s applied to a wall or roof rafters to add strength and keep the building straight and plumb

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Which of the following would NOT be
nikdorinn [45]

Answer:

Option A

hands-on assembly of the company's product

Explanation:

The managerial roles mainly include supervision of actual work on a higher level and implementation of organization's policy. The hands-on assembly of company's product is majorly done by junior staff who work under a supervisor who reports to the manager. Therefore, this is not a duty of a manager in a manufacturing field.

7 0
3 years ago
You want to improve your grades so that you make all A's next 6 weeks. List examples of quantitative and qualitative data you sh
Naddika [18.5K]

Explanation:

z3d33sxurljt 36f

3fभथठभदाफमदखज्ञफादफज्ञादफज्ञिलफ इऋबिअऋब

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3 years ago
Relation between Poisson's ration, young's modulus, shear modulus for an isotropic material
poizon [28]

Answer:

 E=2 G(1+2μ)

Explanation:

Isotropic material :

 Those material have same property in all direction is known as isotropic material.

Homogeneous material :

 Those material have same property through out the volume is known as homogeneous material.

Relationship between Poisson ratio ,young modulus and shear modulus:

   E=2 G(1+2μ)

Relationship between Poisson ratio ,bulk modulus and shear modulus:

E=2 K(1-μ)

Where

E is  young modulus.

G is shear modulus.

μ is Poisson ratio.

 

8 0
3 years ago
A 3.7 g mass is released from rest at C which has a height of 1.1 m above the base of a loop-the-loop and a radius of 0.2 m . Th
Dmitrij [34]

Answer:

Normal force = 0.326N

Explanation:

Given that:

mass released from rest at C = 3.7 g = 3.7 × 10⁻³ kg

height of the mass = 1.1 m

radius = 0.2 m

acceleration due to gravity = 9.8 m/s²

We are to determine the normal force pressing on the track at A.

To to that;

Let consider the conservation of energy relation; which says:

mgh = mgr + 1/2 mv²

gh = gr + 1/2 v²

gh - gr = 1/2v²

g(h-r) = 1/2v²

v² = 2g(h-r)

However; the normal force will result to a centripetal force; as such, using the relation

N =mv²/r

replacing the value for v² = 2g(h-r) in the above relation; we have:

Normal force = 2mg(h-r)/r

Normal force = 2 × 3.7 × 10⁻³ × 9.8 ( 1.1 - 0.2 )/ 0.2

Normal force = 0.065268/0.2

Normal force = 0.32634 N

Normal force = 0.326N

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3 years ago
When is a handrail required for stairs?
Leviafan [203]

Answer:

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5 0
3 years ago
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