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2 years ago

1. A _____ is applied to a wall or roof rafters to add strength and keep the building straight and plumb.

Engineering

1 answer:

PSYCHO15rus [73]2 years ago

7 0

Answer:

A force must s applied to a wall or roof rafters to add strength and keep the building straight and plumb

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A long rod of 60-mm diameter and thermophysical properties rho=8000 kg/m^3, c=500J/kgK, and k=50 W/mK is initally at a uniform t

Monica [59]

Answer:

Tc = 424.85 K

Explanation:

Given that,

$D = 60 mm = 0.06 m$

$\rho = 8000 kg/m^3$

$k = 50 w/m . kc = 500 j/kg.k$

$h_{\infty} = 1000 w/m^2t_{\infity} = 750 kt_w = 500 K$

$surface area = As = \pi dL \\\frac{As}{L} = \pi D = \pi \timeS 0.06$

HEAT FLOW Q is

$Q = h_{\infty} As (T_[\infty} - Tw) = 1000 \pi\times 0.06 (750-500)$

= 47123.88 w per unit length of rod

volumetric heat rate

$q = \frac{Q}{LAs}$

$= \frac{47123.88}{\frac{\pi}{4} D^2 \times 1}$

$q = 1.66\times 10^{7} w/m^3$

$Tc = \frac{- qR^2}{4K} + Tw$

$= \frac{ - 1.67\times 10^7 \times (\frac{0.06}{2})^2}{4\times 50} + 500$

= 424.85 K

3 0

2 years ago

Mention verious medium level and higher level human resources related to engineering

aliya0001 [1]

Answer:

Engineering aims to allow technical parts, structures and/or systems, such as those of a machine, to fulfill their function. To this end, occurring and/or desired processes (the operation thereof) are investigated and elaborated. Appropriate parts are designed individually or in a team, occurring stresses are calculated and the parts to be produced are modeled and/or specified on technical drawings. In some fields, maintenance is a standard part of the work to be performed. For a large part of engineering, standards and agreements have been drawn up with a view to the desired safety and practical applicability.

8 0

2 years ago

A food department is kept at -12 °C by a refrigerator in an environment at 30 °C. The total heat gain to the food department is

Nataly [62]

Answer: P = 0.416 kW

Explanation:

taken a step by step process to solving this problem.

we have that from the question;

the amount of heat rejected Qn = 4800 kJ/h

the cooling effect is Ql = 3300 kJ/h

Applying the first law of thermodynamics for this system gives us

Шnet = Qn -Ql

Шnet = 4800 - 3300 = 1500 kJ/h

Next we would calculate the coefficient of performance of the refrigerator;

COPr = Desired Effect / work output = Ql / Шnet = 3300/1500 = 2.2

COPr = 2.2

The Power as required gives;

P = Qn - Ql = 4800 - 3300 = 1500 kJ/h = 0.416

P = 0.416 kW

cheers i hope this helps!!!!1

5 0

3 years ago

A manufacturer makes integrated circuits that each have a resistance layer with a target thickness of 200 units. A circuit won't

aleksklad [387]

Answer:

probability P = 0.32

Explanation:

this is incomplete question

i found complete A manufactures makes integrated circuits that each have a resistance layer with a target thickness of 200 units. A circuit won't work well if this thickness varies too much from the target value. These thickness measurements are approximately normally distributed with a mean of 200 units and a standard deviation of 12 units. A random sample of 17 measurements is selected for a quality inspection. We can assume that the measurements in the sample are independent. What is the probability that the mean thickness in these 16 measurements x is farther than 3 units away from the target value?

solution

we know that Standard error is expess as

Standard error = $\frac{sd}{\sqrt{n}}$

Standard error = $\frac{12}{\sqrt{16}}$

Standard error = 3

so here we get Z value for 3 units away are from mean are

mean = -1 and + 1

so here

probability P will be

probability P = P( z < -1 or z > 1)

probability P = 0.1587 + 0.1587

probability P = 0.3174

probability P = 0.32

7 0

3 years ago

Leland wants to work in a Production career operating heavy machinery. Which type of education or training should Leland seek?

zhenek [66]

Answer:

it is indeed C

Explanation:

4 0

2 years ago

Read 2 more answers