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3 years ago

1. A _____ is applied to a wall or roof rafters to add strength and keep the building straight and plumb.

Engineering

1 answer:

PSYCHO15rus [73]3 years ago

7 0

Answer:

A force must s applied to a wall or roof rafters to add strength and keep the building straight and plumb

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Air is compressed in a reversible, isothermal, steady- flow process from 15 psia, 100°F to 100 psia. Calculate the work of compr

mixas84 [53]

Answer:

|W|=169.28 KJ/kg

ΔS = -0.544 KJ/Kg.K

Explanation:

Given that

T= 100°F

We know that

1 °F = 255.92 K

100°F = 310 .92 K

$P _1= 15 psia$

$P _1= 100 psia$

We know that work for isothermal process

$W=mRT\ln \dfrac{P_1}{P_2}$

Lets take mass is 1 kg.

So work per unit mass

$W=RT\ln \dfrac{P_1}{P_2}$

We know that for air R=0.287KJ/kg.K

$W=RT\ln \dfrac{P_1}{P_2}$

$W=0.287\times 310.92\ln \dfrac{15}{100}$

W= - 169.28 KJ/kg

Negative sign indicates compression

|W|=169.28 KJ/kg

We know that change in entropy at constant volume

$\Delta S=-R\ln \dfrac{P_2}{P_1}$

$\Delta S=-0.287\ln \dfrac{100}{15}$

ΔS = -0.544 KJ/Kg.K

3 0

3 years ago

Briefly describe an idea for a new product, (which can be anything) while thinking made me about it cost analysis. Depict what k

larisa86 [58]

Answer:

A transforming vechicle that could transform from a land-based vehicle to a water-based vehicle and to an air based vehicle.

Explanation:

7 0

3 years ago

Use phasor techniques to determine the impedance seen by the source given that R = 4 Ω, C = 12 μF, L = 6 mH and ω = 2000 rad/sec

Zielflug [23.3K]

Answer:

Z = 29.938Ω ∠22.04°

I = 2.494A

Explanation:

Impedance Z is defined as the total opposition to the flow of current in an AC circuit. In an R-L-C AC circuit, Impedance is expressed as shown:

Z² = R²+(Xl-Xc)²

Z = √R²+(Xl-Xc)²

R is the resistance = 4Ω

Xl is the inductive reactance = ωL

Xc is the capacitive reactance =

1/ωc

Given C = 12 μF, L = 6 mH and ω = 2000 rad/sec

Xl = 2000×6×10^-3

Xl = 12Ω

Xc = 1/2000×12×10^-6

Xc = 1/24000×10^-6

Xc = 1/0.024

Xc = 41.67Ω

Z = √4²+(12-41.67)²

Z = √16+880.31

Z = √896.31

Z = 29.938Ω (to 3dp)

θ = tan^-1(Xl-Xc)/R

θ = tan^-1(12-41.67)/12

θ = tan^-1(-29.67)/12

θ = tan^-1 -2.47

θ = -67.96°

θ = 90-67.96

θ = 22.04° (to 2dp)

To determine the current, we will use the relationship

V = IZ

I =V/Z

Given V = 12V

I = 29.93/12

I = 2.494A (3dp)

7 0

3 years ago

If you are exposed to potentially infectious material via a sharps injury, what should you do immediately?

Sergio039 [100]

The correct answer is "immediately flood the area with water and clean the wound."

Further Explanation:

If someone is exposed to a potentially infectious material with a sharps item such a needle, they need to wash the area with clean water immediately. It must be a steady flow of water to get out any potential infectious material.

After flushing the injury with water, you will then wash the area or exposed skin with soap, if at all possible use a disinfectant on the area.

The person who was injured should seek medical assistance for tests to be sure that they have not been affected.

Learn more about infectious material at brainly.com/question/10928952

#LearnwithBrainly

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3 years ago

A hypothetical accumulator processor uses one of the following 16-bit instruction formats, depending on the instruction.(a) (10

Jlenok [28]

Answer:

Every part has been answered with complete detail. See the pictures.

Explanation:

See the pictures for detailed answer.

7 0

3 years ago