Question

A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult. Assuming the acceleration is constant, how far did it travel during those 2.0 s?

Answer 1

First find Acceleration

• Initial velocity=u=0m/s
• Final velocity=v=42m/s
• Time=t=2s
• Distance=s
• Acceleration=a

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto Acceleration=\dfrac{42-0}{2}$

$\\ \sf\longmapsto Acceleration=\dfrac{42}{2}$

$\\ \sf\longmapsto Acceleration=21m/s^2$

Using second equation of kinematics

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}(21)(2)^2$

$\\ \sf\longmapsto s=21(2)$

$\\ \sf\longmapsto s=42m$