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torisob [31]
2 years ago
7

Two forces whose resultant is 100N are at right angle to eachother. if one of them makes an angle of 30° with the resultant, det

ermine its magnitude​
Physics
1 answer:
mihalych1998 [28]2 years ago
8 0

Let <em>F₁ </em>and <em>F₂</em> denote the two forces, and <em>R</em> the resultant force.

<em>F₁ </em>and <em>F₂</em> point perpendicularly to one another, so their dot product is

<em>F₁ </em>• <em>F₂</em> = 0

<em />

We're given that one of these vectors, say <em>F₁</em>, makes an angle with <em>R</em> of 30°, so that

<em>F₁</em> • <em>R</em> = ||<em>F₁</em>|| ||<em>R</em>|| cos(30°)

But we also have

<em>F₁</em> • <em>R</em> = <em>F₁ </em>• (<em>F₁ </em>+ <em>F₂</em>) = (<em>F₁ </em>• <em>F₁</em>) + (<em>F₁ </em>• <em>F₂</em>) = <em>F₁ </em>• <em>F₁ </em>=<em> </em>||<em>F₁</em>||²

So, knowing that ||<em>R</em>|| = 100 N, we get that

(100 N) ||<em>F₁</em>|| cos(30°) = ||<em>F₁</em>||²

(100 N) cos(30°) = ||<em>F₁</em>||

||<em>F₁</em>|| ≈ 86.6 N

(And the same would be true for <em>F₂</em>.)

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I hope it's helpful!

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lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pu
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In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:

\begin{gathered} W=(17)(12)\cos0+(36)(12)\cos30 \\ W=578.123 \end{gathered}

Therefore, the total work done is 578.123 J and the answer is option E

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1 year ago
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3 years ago
1) A train accelerates from 36 km/hr to 54 km/hr in 10<br> s. Find acceleration?
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Answer: Given:

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Final velocity =54km/h=54x5/18=15m/s

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False, the values ​​of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.

Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.

<u>xXCherryCakeXx</u>.

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