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Sveta_85 [38]
3 years ago
5

Hydraulic fracturing is: Select one: a. a first step in storage of high-level radioactive waste b. a way of extracting natural g

as shale formations c. a step in oil refining where oil is separated into different viscosities d. none of the above
Engineering
1 answer:
lorasvet [3.4K]3 years ago
4 0
The answer is B - a way of extracting natural gas shale formations.

Hydraulic fracturing is “a way of extracting natural gas shale formations.”
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pochemuha

Answer:

I think this answer is number B

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In terms of the atomic radius, R, determine the distance between the centers of adjacent atoms for the FCC crystal structure alo
timama [110]

Answer:

The distance between the centers of adjacent atoms for the FCC crystal structure along the [100] is 2R√2

Explanation:

From the image uploaded, a Face centered cubic structure (100) plane, there is one atom at each of the four cube corners, each of which is shared with four adjacent unit cells, while the center atom lies entirely within the unit cell.

In terms of the atomic radius, R, we determine the distance between the centers of adjacent atoms.

Let this distance = AC

the two adjacent sides = AB and BC

AB = a = 2R

BC = a = 2R

Using Pythagoras theorem

AC² = AB² + BC²

AC² = a² + a²

AC² = 2a²

AC = √2a²

AC = a√2

But a = 2R

AC = 2R√2

Therefore,  the distance between the centers of adjacent atoms for the FCC crystal structure along the [100] is 2R√2

6 0
3 years ago
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bearhunter [10]

Answer:

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Explanation:

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Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.
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Correct answer is option E. No dimensions

As we know formula Pressure (P) is \frac{F}{A}

also,

  • Dimensional formula of <em>Pressure is </em>M^{1}L^{-1}T^{-2}
  • Dimensional formula of <em>length is L </em>
  • Dimensional formula of <em>mass is M</em>
  • Dimensional formula  of <em>velocity is </em>L^{1} T^{-1}

So, as given W=\frac{P*L^{3} }{M*V^{2} }

Dimensional formula of W =\frac{M^{1}L^{-1}T^{-2}  L^{3}  }{M^{1} L^{2}T^{-2}   }

since all terms get cancelled

Work is dimensionless i.e no dimensions

Learn more about dimensions here brainly.com/question/20351712

#SPJ10

6 0
2 years ago
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