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8090 [49]
2 years ago
8

Which formula is comparing a sample of a gas under two different conditions of volume and temperature, if the pressure is consta

nt?
⚪︎ V1 V2

____ = ___

T1 T2


⚪︎ xy = k


⚪︎ V

__ = k

T


⚪︎ P1V1 = P2V2


⚪︎ PV = k
Chemistry
1 answer:
Gwar [14]2 years ago
3 0

Answer:

V1/T1 = V2/T2

Explanation:

The Combined gas law for two states, 1 and 2, is given by:

P1V1/T1 = P2V2/T2

where P, V, and T are Pressure, Volume, and Temperature (always in degrees Kelvin).

If pressure is constant, the P1 and P2 cancel out:

V1/T1 = V2/T2

I can't tell from the formatting of the answers if A is this relationship.  Please compare.

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A sample of Ne gas has a pressure of 654 mmHg with an unknown volume. The gas has a pressure of 345 mmHg when the volume is 495m
Lemur [1.5K]

Answer:

The initial volume of Ne gas is 261mL

Explanation:

This question can be answered using Ideal Gas Equation;

However, the following are the given parameters

Initial Pressure = 654mmHg

Finial Pressure = 345mmHg

Final Volume = 495mL

Required

Initial Volume?

The question says that Temperature is constant;

This implies that, we'll make use of Boyle's law ideal gas equation which states;

P_1V_1 = P_2V_2

Where P_1 represent the initial pressure

P_2 represent the final pressure

T_1 represent the initial temperature

T_2 represent the final temperature

P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL

Substitute these values in the formula above;

654 * V_1 = 345 * 495

654V_1 = 170775

Divide both sides by 654

\frac{654V_1}{654} = \frac{170775}{654}

V_1 = \frac{170775}{654}

V_1 = 261.123853211

V_1 = 261mL (Approximated)

<em>The initial volume of Ne gas is 261mL</em>

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