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3 years ago

Show that 2sinøcosø =sin2ø

Physics

1 answer:

bulgar [2K]3 years ago

8 0

https://www.dailymotion.com/video/x4ug3zm

watch this video and u will get answer

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Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water. If the cylinder

jonny [76]

Answer:

0.10839 m

Explanation:

$P_1$ = Atmospheric pressure = 1 atm = 101325 Pa

$P$ = Total pressure at bottom of mecury = 1.2 atm

g = Acceleration due to gravity = 9.81 m/s²

h = d = Depth of mercury

$\rho_m$ = Density of mercury = $1.36\times 10^4\ kg/m^3$

$\rho_w$ = Density of water = $1000\ kg/m^3$

Pressure at the bottom is of the cylinder is given by

$P_2=P_1+\rho_wgh\\\Rightarrow P_2=101325+1000\times 9.81(0.7-d)$

Pressure at the bottom of mercury is

$P=P_2+\rho_mgh\\\Rightarrow 1.2\times 101325=101325+1000\times 9.81(0.7-d)+1.36\times 10^4\times 9.81\times d\\\Rightarrow 1.2\times 101325=123606d+108192\\\Rightarrow d=\dfrac{1.2\times 101325-108192}{123606}\\\Rightarrow d=0.10839\ m$

The depth of the mercury is 0.10839 m

7 0

3 years ago

2. What is the percent composition of sulfur in H2SO4?

allochka39001 [22]

Answer:

C. 32.7%

Explanation:

% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest

6 0

3 years ago

3.) If Lebron James has a vertical leap of +1.35 m. then what is his takeoff speed7 For this

Scilla [17]

D, I hoped that helped you

7 0

4 years ago

Read 2 more answers

Is the water the same temperature in alaska and mexico?

Snezhnost [94]

Colder in Alaska, warmer in Mexico.

6 0

3 years ago

Two identical charges, each -8.00 E-5 C, are separated by a distance of 20.0 cm (100 cm = 1 m). What is the force of repulsion?

Rom4ik [11]

F = 1440 N. The repulsion force between two identical charges, each -8.00x10⁻⁵C separated by a distance of 20.0 cm is 1440 N.

The easiest way to solve this problem is using Coulomb's Law given by the equation $F=k\frac{|q_{1}*q_{2}|}{r^{2} }$ , where k is the constant of proportionality or Coulomb's constant, q₁ and q₂ are the charges magnitude, and r is the distance between them.

We have to identical charges of -8.00x10⁻⁵C, are separated by a distance of 20.0 cm, and we need to know the force of repulsion between the charges.

First, we have to convert 20.0 cm to meters.

(20.0 cm x 1m)/100cm = 0.20 m

Using the Coulomb's Law equation:

$F = 9.00x10^{9}\frac{Nm^{2}}{C^{2}} \frac{|-8.00x10^{-5}C*-8.00x10^{-5}C|}{(0.20m)^{2} }$

$F = 9.00x10^{9}\frac{Nm^{2}}{C^{2}}(1.6x10^-7\frac{C^{2} }{m^{2} } })\\F = 1440N$

5 0

3 years ago

Show that 2sinøcosø =sin2ø​

Show that 2sinøcosø =sin2ø